I have this array:
["onelolone", "twololtwo", "three"]
How can I remove the elements using only 'lol' as value and as result be:
["three"]
-
3Does this answer your question? Remove all elements from array that match specific stringAchtung– Achtung2021-01-04 00:03:09 +00:00Commented Jan 4, 2021 at 0:03
-
You wanna remove the items that don't contain "lol"?Hef– Hef2021-01-04 00:03:21 +00:00Commented Jan 4, 2021 at 0:03
-
developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…S. Walker– S. Walker2021-01-04 00:03:29 +00:00Commented Jan 4, 2021 at 0:03
Add a comment
|
2 Answers
Use Array.prototype.filter, and check that it doesn't include "lol":
const result = ["onelolone","twololtwo","three"].filter(ele => !ele.includes("lol"))
console.log(result)// ["three"]
Array#filter is used to keep elements that satisfy a predicate. But we can build a reject function that removes the elements that satisfy a predicate:
const reject = fn => xs => xs.filter(x => fn(x) === false);
Then we can build a curried function for matching a string:
const matches = x => y => y.includes(x);
const reject_lol = reject(matches("lol"));
reject_lol(["onelolone", "twololtwo", "three"]);
//=> ["three"]
We can tweak matches to support any number of strings:
const matches = (...xs) => y => xs.some(x => y.includes(x));
const reject_abbr = reject(matches("lol", "wtf"));
reject_abbr(["lolone", "twowtf", "three"]);
//=> ["three"]
