calling a codeigniter controller method from jquery

Question

I wanted to call a codeigniter controller method from within jquery as of now I am trying something like this but it isn't working could anyone help me out with this

$.ajax({type: "POST", url:"site/controller/method/",

                  success: function(){
                      alert("success");
                  },

                  error: function(xhr, textStatus, error){
                              alert(xhr.statusText);
                              alert(textStatus);
                              alert(error);
                          }

               });

Can you elaborate please? Your question is very vague. Generally 'not working' is not a good explanation. — Mrchief
– Mrchief, Commented Jun 30, 2011 at 2:44
you need to set the full path on your url, like: http:localhost/site/controller/method/, I use it this way and works properly and you can pass variables with the 'data:' or in your URL — user745235
– user745235, Commented Jun 30, 2011 at 20:35

drfranks3 · Accepted Answer · 2011-06-30 02:48:56Z

3

I myself use CI, and have found that I need to point directly to the file when processing AJAX requests, and if needed, push some variables with it.

$.ajax({
    type: "POST",
    url: "system/application/views/ajax.php",
    data: "key=value",
    success: function(){ alert("success"); },
    error: function(xhr, textStatus, error){
        alert(xhr.statusText);
        alert(textStatus);
        alert(error);
     }
});

answered Jun 30, 2011 at 2:48

drfranks3

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3 Comments

koool Over a year ago

@D Franks thanks for the answer but how do I just call a particular method within a controller, By the above procedure I would be able to reach the controller but not the method within a controller and I hope there is a way to address this problem

drfranks3 Over a year ago

Although I don't think there is a way to do this directly (or I'm unaware of), you could either add an if statement to run your method, e.g.: if($_POST['call-from-ajax']){ run_method(); }, or you could look into this I found in the CI wiki: codeigniter.com/wiki/AJAX_for_CodeIgniter

Brad Over a year ago

@ D Franks, you can use site_url() in place of the system/application part. $.ajax({ url: "<?php echo site_url('forms/textup'); ?>",

Femi · Accepted Answer · 2011-06-30 03:55:28Z

Your question is very vague: did you get a 404? Did you get a javascript error? What was the problem?

If you are having 404 errors the easiest way to make this work is to test out the URL in your browser's location bar: any URL you can open in the browser location bar can be copied into the javascript and will definitely work. There should be no difference on the code igniter side between URLs that are called from the browser location bar or from an anchor and URLs that are called from a jquery post or get or ajax.

I'd recommend using Firebug to look at the activity going on under the hood: it might make pinpointing these errors easier for you.

I used mozilla firefox web console and usually it shows the post request, but, i this case the problem is there is no post request shown and there is no error

The Silencer · Accepted Answer · 2011-06-30 12:40:23Z

I made a controller called ajax, where i have all my axaj methods. And return stuff json encoded.

jquery stuff:

    $.post("ajax/stuff", function(data){
    alert(data.some_data); // John
 }, "json");

in ajax controller:

public function stuff()
{
    $response_array = array();
    $response_array['some_data'] = 'lorem ipsum';
    //$response_array['html'] = $this->load->view('popbox_error', $data, true);

    $data['json'] = json_encode($response_array);
    $this->load->view('json_response', $data);
}

json view:

<?php echo $json;

can explain further on $.post("ajax/stuff" . i dont really know what should i put there. im new in ajax. :) thanks in advance

Shaolin · Accepted Answer · 2012-09-26 06:53:20Z

0

Try this

var base_url ='your base url;

$.post(base_url+"/controller/function", {'param1': x,'param2':y}, function(data){

        if(data.length >0) {

            //do whatever you want

        }
    });

answered Sep 26, 2012 at 6:53

Shaolin

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