How can I copy one array to another in C and get two separate arrays?

Question

I need to copy an array to another, then change copied array without affecting the original one. I tried:

memcpy(statesVactor,denominatorFactors,n *sizeof(int));
and
memmove(statesVector,denominatorFactors,n *sizeof(int));
But still when I multiply statesVector by -1, denominatorFactors multiplies as well. I feel, I don't understand sth simple.

EDIT:

int n = 0; 
int denominatorFactors[n];
int statesVector[n];
 scanf("%d", &n);
memmove(statesVector,denominatorFactors,n *sizeof(int)); //or 
//memcpy(statesVactor,denominatorFactors,n *sizeof(int)); 

for(int i = 0; i<n;i++){
        statesVector[i] = -1 * statesVector[i];
    }

for(int i = 0; i<n;i++){
        printf("%d\t",statesVector[i]);
    }
for(int i = 0; i<n;i++) {
         printf("%d",denominatorFactors[i]);
        }

Answer 1

You can't initialize the size of array at 0 (int n = 0; int denominatorFactors[n])

You declarate your array after you read the size not before

#include<stdio.h>

int main(void)
{
    int size;
    do
    {
         printf("Give the size of your array :");
         scanf("%d",&size);
    }while(size <1);
    int statesVector[size];
    int denominatorFactors[size];
    for(int i = 0; i<size;i++)
    {
        printf("Give me the %d elment :",i);
        scanf("%d",&statesVector[i]);
        denominatorFactors[i] = statesVector[i];
    }
    printf("\n\nDisplay of the original array :\n\n");
    for(int i = 0; i<size;i++)
    {
        printf("[%d]\t",statesVector[i]);
    }
    printf("\n\nDisplay of the copy of array :\n\n");
    for(int i = 0; i<size;i++)
    {
        denominatorFactors[i]*=-1;
        printf("[%d]\t",denominatorFactors[i]);
    }
    printf("\n");
    return 0;
}