Print url when element is a link in Python-Selenium

Question

I'm using Python3 and Selenium. The xpath below points to a link. I would like to print the URL. If I write print(link.text) I get the displayed text portion of the link only. For example: link.text in the following link would give me "link text" when I want URL.

HTML:

<a href="url">link text</a>

Code trials:

path = f"/html/body/div/section[5]/div/div/div[1]/div[3]/div[{str(n)}]/div/div[1]/div/div[2]/div[1]/a"
link = driver.find_element_by_xpath(path)
print(link.url)

DonnyFlaw · Accepted Answer · 2020-11-24 22:55:58Z

2

You need to use

link.get_attribute('href')

instead of

link.text

answered Nov 24, 2020 at 22:55

DonnyFlaw

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Comments

undetected Selenium · Accepted Answer · 2020-11-25 03:47:00Z

1

print(link.text) would print the text / textContent / innerHTML of the <a> WebElement i.e.

link text

If your usecase is to print the value of the href attribute i.e. url you can use the following solution:

print(link.get_attribute("href"))

answered Nov 25, 2020 at 3:47

undetected Selenium

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