Try and except return value Python

Question

Hi this is my code i want it to return 'A' but it keeps printing none. I don't know what is the error. Thanks for helping.

def example(inputClass):
    try:
        obj = inputClass()
        obj.errCheck()
    except ValueError as e:
        return e


def example2():
    class test(): 
        def __init__(self):
            pass
        def errCheck(test):
            raise ValueError('A')
    example(test)


def main():
    print(example2())

if __name__ == '__main__':
    main()

example2() has no explicit return so it returns None

buran
– buran

2020-11-12 05:33:10 +00:00
Commented Nov 12, 2020 at 5:33 — buran
– buran, Commented Nov 12, 2020 at 5:33

TigerhawkT3 · Accepted Answer · 2020-11-12 05:32:47Z

2

You need to return the value of example(test) to the caller.

def example2():
    class test(): 
        def __init__(self):
            pass
        def errCheck(test):
            raise ValueError('A')
    return example(test) # this line

answered Nov 12, 2020 at 5:32

TigerhawkT3

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