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I have a question regarding a dictionary in python and empty values. If I had the following dictionary

my_dict={'a':[],
 'b':[1],
 'c':[],
 'd':[]
}

How I could remove empty values [] and appending the keys in an empty list?

my_dict={
 'b':[1],
}

and empty_list=['a','c','d']. With a list I would do as follows (but there are several ways to do the same):

my_dict = list(filter(None, my_dict))

But I have realised I do not know how to do the same in a dictionary.

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    {k:v for k,v in my_dict.items() if v is not None}? Commented Oct 11, 2020 at 18:25
  • Hi Marcin, it answers partially. I am still not understand how to remove empty values :( Commented Oct 11, 2020 at 18:25
  • thanks @yatu. I have not tried it yet. Thanks a lot Commented Oct 11, 2020 at 18:26
  • seriously, sometimes it is hard for me to understand the reason why some questions are down voted and some others (with no reproducible data, no attempt of solution, ...) are not :/ Commented Oct 11, 2020 at 18:43

2 Answers 2

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You can use a dict comprehension to remove empty values:

new_dict = {k: v for k, v in my_dict.items() if v}

Then you can use set difference to get the removed keys:

removed_keys = my_dict.keys() - new_dict.keys()
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Just do two explicit iterations for a clean solution -- first calculate the empty_list, then filter down my_dict:

empty_list = [k for k, v in my_dict.items() if len(v) == 0]
my_dict = {k: v for k, v in my_dict.items() if len(v) != 0}
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