How can I name output file by including the input file name in a function

Question

I'm trying to name an output file by adding the string "resampled" to the input file name

outputfile = '%s.tif' % '{0}+ {1}'.format(inputfile, '_resampled')

How can I do this so my output file is saved as inputfile_resampled.tif?

For example:

NIR would become NIR_resampled.tif.

Why the complicated-double string formatting? Why not just "{}.tif".format(inputfile+ '_resampled')? — Tomerikoo
– Tomerikoo, Commented Oct 4, 2020 at 12:04
Does this answer your question? How to add an id to filename before extension? ; or stackoverflow.com/questions/24409984/… — Tomerikoo
– Tomerikoo, Commented Oct 4, 2020 at 12:06
``` "{}.tif".format(inputfile+ '_resampled')``` didn't work! — Farid ATMANI
– Farid ATMANI, Commented Oct 4, 2020 at 12:18
Check out the links above. That should give you your answer. The above suggestion will not work if inputfile is a full path and not just the file's name... — Tomerikoo
– Tomerikoo, Commented Oct 4, 2020 at 12:20

mujjiga · Accepted Answer · 2020-10-04 12:19:20Z

1

Using f-string

outputfile = f"{inputfile}_resampled.tif"

Using standard string

outputfile = "{}_resampled.tif".format(inputfile)

answered Oct 4, 2020 at 12:19

mujjiga

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