How to convert a string to JSON in JavaScript

Question

In my application I am getting a response like below:

{"success":true,"data":"{\"status\": \"Failed\", \"percentage_completed\": \"0\", \"actions\": \"Error: Insufficient argument: 1\\n\"}","message":"Logs fetched successfully."}

How can I convert this into JSON? I tried JSON.parse, but it doesn’t seem to work. Is there another way to convert this string into a valid JSON format?

That string is already in JSON format. Do you mean you want to parse it into a JavaScript object? — zcoop98
– zcoop98, Commented Sep 30, 2020 at 20:35
What about JSON.parse() didn't work? Did you get an error message? — zcoop98
– zcoop98, Commented Sep 30, 2020 at 20:36
Does this answer your question? How to parse JSON string in Typescript — gurisko
– gurisko, Commented Sep 30, 2020 at 20:36
Looks like this is ajax call response. You want to use JSON.parse(response.data). — Dipen Shah
– Dipen Shah, Commented Sep 30, 2020 at 20:37

GLJ · Accepted Answer · 2020-09-30 20:39:36Z

25

I understand where the confusion is coming from. The provided object has a property which contains a JSON string. In this case, the "data" attribute contains the JSON string which you need to parse. Look at the following example.

var result = {"success":true,"data":"{\"status\": \"Failed\", \"percentage_completed\": \"0\", \"actions\": \"Error: Insufficient argument: 1\\n\"}","message":"Logs fetched successfully."};

JSON.parse(result); // should fail
JSON.parse(result["data"]); // should work
JSON.parse(result.data) // or if you prefer this notation

answered Sep 30, 2020 at 20:39

GLJ

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Comments

Peter Mortensen · Accepted Answer · 2023-02-22 05:08:37Z

0

Try this:

let data = {"success":true,"data":"{\"status\": \"Failed\", \"percentage_completed\": \"0\", \"actions\": \"Error: Insufficient argument: 1\\n\"}","message":"Logs fetched successfully."}
data.data = JSON.parse(data.data);
console.log(data);

edited Feb 22, 2023 at 5:08

Peter Mortensen

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answered Feb 21, 2023 at 1:21

Jordy

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1 Comment

Peter Mortensen Over a year ago

Re "Try this": An explanation would be in order. E.g., what kind of JSON input is it? Invalid? Valid? The same? Different? What is the idea/gist? What did you change and why? From the Help Center: "...always explain why the solution you're presenting is appropriate and how it works". Please respond by editing (changing) your answer, not here in comments (*** without *** "Edit:", "Update:", or similar - the answer should appear as if it was written today).

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