Check if string is in a list

Question

I've seen many solutions of this type of problem but I can't really find one that I'm looking for.

For example:

text = ['hi', 'hello', 'hey']
user_input = input('Enter something: ')

for word in user_input:
    if word in text:
        print('Hi')
    else:
        print('Bye')

If the user_input was "hi there", it would give me back

Bye
Bye
Bye
Bye
Bye
Bye
Bye
Bye

How can I check to see if at least one of the words in user_input is in the list (text)?

Answer 1

You can try this:

text = ['hi', 'hello', 'hey']
user_input = input('Enter something: ')

for word in user_input.split(" "):
    if word in text:
        print('Hi')
    else:
        print('Bye')

Another Option:

text = ['hi', 'hello', 'hey']
user_input = input('Enter something: ')

flag = "Y"
for word in user_input.split(" "):
    if word in text:
        print('Matched String:', word)
    else:
        flag = "N"

if flag == "N":
    print("Unmatched String Exists")

Answer 2

in addition to the others answer, two more options:

1. using .index()
2. using a filter in pandas.DataFrame

Option 2 is advantageous as it shows all hits, while option 1 only shows the first hit but is more "pythonic".

Option 1:

text = ['hi', 'hello', 'hey']
user_input = input('Enter something: ')

try:
    text.index(user_input)
    print('Hi')
except ValueError:
    print('Bye')

try...except is implemented due to the problem that .index() drops an error in the case that the search string is not in the list.

Option 2:

import pandas as pd
text = ['hi', 'hello', 'hey']
user_input = input('Enter something: ')
df=pd.DataFrame(text)
result=df[df[0]==user_input]
if len(result)>0: 
    print('Hi')
    [print(result[i]) for i in range(len(result))]
else:
    print('Bye')