Passing Variables in URL - PHP

Question

Assume that I have a URL like this

http://subdomain.domain.com/folder1/abc?cat1=PTO2Cat2=HITOFF&u=%2Fnetahtml%2FPTO%2Fsearch-adv.htm&TEXT1=Value

In this URL, TEXT1 at the end keeps changing for various pages. The Value will not change though. So it will be something like

For Page 1

http://subdomain.domain.com/folder1/abc?cat1=PTO2Cat2=HITOFF&u=%2Fnetahtml%2FPTO%2Fsearch-adv.htm&TEXT1=Value

For Page 2

http://subdomain.domain.com/folder1/abc?cat1=PTO2Cat2=HITOFF&u=%2Fnetahtml%2FPTO%2Fsearch-adv.htm&TEXT2=Value

For Page n

http://subdomain.domain.com/folder1/abc?cat1=PTO2Cat2=HITOFF&u=%2Fnetahtml%2FPTO%2Fsearch-adv.htm&TEXTn=Value

How can I parametrize it? I tried something like this

for ($i=1;$i<=n;$i++)
{
$url = sprintf('http://subdomain.domain.com/folder1/abc?cat1=PTO2Cat2=HITOFF&u=%2Fnetahtml%2FPTO%2Fsearch-adv.htm&TEXT%d=Value',$i)
echo $url;
}

but it failed saying Sprintf too few arguments. Any suggestion, please?

OverLex · Accepted Answer · 2011-06-20 10:24:13Z

5

You have more than one % sign in that url, sprintf parses it and tries to assign arguments to every %'something' it finds, you should escape the url encoded values.

You might want to check: http://www.php.net/manual/en/function.sprintf.php

answered Jun 20, 2011 at 10:24

OverLex

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1 Comment

SaidbakR Over a year ago

I added an answer to show simple way to escape the encoded values of the URL.

Shakti Singh · Accepted Answer · 2011-06-20 10:26:29Z

1

Just use urldecode because the more than one (additional)% is creating problem .

$url=urldecode('http://subdomain.domain.com/folder1/abc?cat1=PTO2Cat2=HITOFF&u=%2Fnetahtml%2FPTO%2Fsearch-adv.htm&TEXT%d=Value');
$url = sprintf($url,$i);

answered Jun 20, 2011 at 10:26

Shakti Singh

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Comments

Sascha Galley · Accepted Answer · 2011-06-20 10:23:05Z

0

$url = 'http://subdomain.domain.com/folder1/abc?cat1=PTO2Cat2=HITOFF&u=%2Fnetahtml%2FPTO%2Fsearch-adv.htm&TEXT'.$i.'=Value';

answered Jun 20, 2011 at 10:23

Sascha Galley

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Balanivash · Accepted Answer · 2011-06-20 10:23:22Z

0

You can use the normal string also right, instead of using sprintf

 for ($i=1 ; $i < = n ; $i++ )
  {
    $url = "http://subdomain.domain.com/folder1/abc?cat1=PTO2Cat2=HITOFF&u=%2Fnetahtml%2FPTO%2Fsearch-adv.htm&TEXT".$i."=Value";
    echo $url;
 }

answered Jun 20, 2011 at 10:23

Balanivash

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Comments

SaidbakR · Accepted Answer · 2014-07-12 20:38:56Z

0

I have got like this issue with using file_get_contents that get url query for solr search engine. I just solved it by escaping the % percent sign in the url encoded string by adding an extra % before every % in the string as follows:

$str = "%s?q=WebSite:%s&sort=Date%%20desc&version=2.2&start=%s&rows=%s&indent=on&wt=json";
        return sprintf($str, $this->url, $this->website, $this->start, $rows);

Notice the double % after the Date in the string.

answered Jul 12, 2014 at 20:38

SaidbakR

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