Here is exercice and example
Binary with 0 and 1 is good, but binary with only 0, or almost, is even better! Originally, this is a concept designed by Chuck Norris to send so called unary messages.
Write a program that takes an incoming message as input and displays as output the message encoded using Chuck Norris’ method.
Rules
Here is the encoding principle:
The input message consists of ASCII characters (7-bit) The encoded output message consists of blocks of 0 A block is separated from another block by a space Two consecutive blocks are used to produce a series of same value bits (only 1 or 0 values): - First block: it is always 0 or 00. If it is 0, then the series contains 1, if not, it contains 0 - Second block: the number of 0 in this block is the number of bits in the series Example Let’s take a simple example with a message which consists of only one character: Capital C. C in binary is represented as 1000011, so with Chuck Norris’ technique this gives:
0 0 (the first series consists of only a single 1) 00 0000 (the second series consists of four 0) 0 00 (the third consists of two 1) So C is coded as: 0 0 00 0000 0 00Second example, we want to encode the message CC (i.e. the 14 bits 10000111000011) :
0 0 (one single 1) 00 0000 (four 0) 0 000 (three 1) 00 0000 (four 0) 0 00 (two 1) So CC is coded as: 0 0 00 0000 0 000 00 0000 0 00
I m stuck on the string "%";
const MESSAGE = "%";
let binaryMess="";
for(let i = 0; i<MESSAGE.length; i++){
binaryMess += MESSAGE.charCodeAt(i).toString(2);
}
const regex = /(1*)(0*)/g;
const answer = binaryMess.replace(regex, (str, g1, g2)=>{
let a="", b="";
if(g1)a = "0 "+"0".repeat(g1.length);
if(g2)b = "00 "+"0".repeat(g2.length);
if(a&&b){return a + " " + b + " ";}
else if(a){return a + " "}
else if(b){return b + " "}
else{return ""}
});
console.log(answer.trim());
The result => Failure Found: 0 0 00 00 0 0 00 0 0 0 Expected: 00 0 0 0 00 00 0 0 00 0 0 0
Any idea why it s not working? I managed to do it with "c" "cc" but didn't with "%" and "Chuck Norris' keyboard has 2 keys: 0 and white space."
.toString(2).padStart(7, "0");would probably help, yet maybe not fix everything.