Generating a list of consecutive numbers as strings [duplicate]

Question

I would like to generate a list of numbers such as this:

['1','2','3','4','5','6']

but all I can seem to get is:

[1, 2, 3, 4, 5, 6]

using this code:

values = list(range(1,7))

Is there some easy way to generate a list of consecutive numbers, that are within apostrophes, since I want the code to treat them like a string.

I have tried:

values = str(list(range(1,7)))

but that just gave me the same result as above.

Cory Kramer · Accepted Answer · 2020-04-03 16:23:14Z

3

>>> [str(i) for i in range(1,7)]
['1', '2', '3', '4', '5', '6']

answered Apr 3, 2020 at 16:23

Cory Kramer

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Comments

user2390182 · Accepted Answer · 2020-04-03 16:26:53Z

1

The comprehension proposed by @CoryKramer has you covered, but given your attempts, you might be looking for:

>>> list(map(str, range(1, 7)))
['1', '2', '3', '4', '5', '6']

answered Apr 3, 2020 at 16:26

user2390182

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user2390182 · Accepted Answer · 2020-04-03 16:34:23Z

1

Try the following:

list(map(str, range(1,7)))

user2390182

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answered Apr 3, 2020 at 16:26

Gabio

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