I'm trying to create 2 variables via bash $lat, $long base on the result of my curl response.
curl ipinfo.io/33.62.137.111 | grep "loc" | awk '{print $2}'
I got.
"42.6334,-71.3162",
I'm trying to get
$lat=42.6334
$long=-71.3162
Can someone give me a little push ?
IFS=, read -r lat long < <(
curl -s ipinfo.io/33.62.137.111 |
jq -r '.loc'
)
printf 'Latitude is: %s\nLongitude is: %s\n' "$lat" "$long"
The ipinfo.io API is returning JSON data, so let parse it with jq:
Here is the JSON as returned by the query from your sample:
{
"ip": "33.62.137.111",
"city": "Columbus",
"region": "Ohio",
"country": "US",
"loc": "39.9690,-83.0114",
"postal": "43218",
"timezone": "America/New_York",
"readme": "https://ipinfo.io/missingauth"
}
We are going to JSON query the loc entry from the main root object ..
curl -s ipinfo.io/33.62.137.111: download the JSON data -s silently without progress.jq -r '.loc': Process JSON data, query the loc entry of the main object and -r output raw string.IFS=, read -r lat long < <(: Sets the Internal Field Separator to , and read both lat and long variables from the following command group output stream.
jq ? and why we need < < ? What is the first one do vs. the second one ?
jq is a json parser <( is called process substitution which is specific to bash afaik.. in front .loc does ?Although the answer from @LeaGris is quite interesting, if you don't want to use an external library or something, you can try this:
Playground: https://repl.it/repls/ThoughtfulImpressiveComputer
coordinates=($(curl ipinfo.io/33.62.137.111 | sed 's/ //g' | grep -P '(?<=\"loc\":").*?(?=\")' -o | tr ',' ' '))
echo "${coordinates[@]}"
echo ${coordinates[0]}
echo ${coordinates[1]}
Example output:
39.9690 -83.0114 # echo "${coordinates[@]}"
39.9690 # ${coordinates[0]}
-83.0114 # ${coordinates[1]}
Explanation:
curl ... get the JSON data
sed 's/ //g' remove all spaces
grep -P ... -o
-P interpret the given pattern as a perl regexp(?<=\"loc\":").*?(?=\")
(?<=\"loc\":") regex lookbehind.*? capture the longitude and latitude part with non-greedy search(?=\") regex lookahead-o get only the matching part which'ld be e.g. 39.9690,-83.0114tr ',' ' ' replace , with space
Finally we got something like this: 39.9690 -83.0114
Putting it in parentheses lets us create an array with two values in it (cf. ${coordinates[...]}).
jq you can extract with sed: read -r lat long < <(curl -s ipinfo.io/33.62.137.111 | sed -n 's/.*\"loc\"[[:space:]]*:[[:space:]]*\"\([[:digit:].]\+\),\([[:digit:].]\+\)\".*/\1 \2/p')
* (0 or more) amount of spaces. They are optional per the JSON syntax.