Newtonsoft.Json C# :: Formatting JsonConvert.SerializeObject

Question

I have following classes,

  public class Actions
        {
            public string say { get; set; }
            public bool? listen { get; set; }
        }

        public class ActionsWrapper 
        { 
            public List<Actions> actions { get; set; }
            public ActionsWrapper(string say, bool listen = false)
            {
                this.actions = new List<Actions>();

                var action = new Actions();
                action.say = say;
                action.listen = listen;
                this.actions.Add(action);
            }
        }

And I am using the following to generate Json

var actions = new ActionsWrapper(say: "Hi, how can I help you today?");
return JsonConvert.SerializeObject(actions);

This returns me following Json,

{"actions":[
      {
        "say":"Hi, how can I help you today?",
         "listen": false
       }
]}

Which is good, but I am sending this to Twilio API which has the requirement of the following format,

{
  "actions": [
    {
      "say": "Hi, how can I help you today?"
    },
    {
      "listen": false
    }
  ]
}

So my question is, what changes do I need in my classes / NewtonSoft to get each property [say&listen] in separate curly braces?

"separate curly brackets" in JSON means it is an object. In your class, they are string and bool values. You can create classes for each of them. Or you could use JSON converter. — weichch
– weichch, Commented Mar 29, 2020 at 10:25

Sina Hoseinkhani · Accepted Answer · 2020-03-29 12:26:31Z

A solution using Newtonsoft.Json:

public class Say
{
    public string say { get; set; }
}

public class Listen
{
    public bool? listen { get; set; }
}

public class ActionsWrapper
{
    public List<Say> Says { get; set; }
    public List<Listen> Listens { get; set; }
    public ActionsWrapper(string say, bool listen = false)
    {
        this.Says = new List<Say>();
        this.Listens = new List<Listen>();
        Says.Add(new Say() { say = say });
        Listens.Add(new Listen() { listen = listen });
    }
}

Usage:

var actions = new ActionsWrapper(say: "Hi, how can I help you today?");

JArray JArraySays = JArray.FromObject(actions.Says);
JArray JArrayListens = JArray.FromObject(actions.Listens);
JArraySays.Merge(JArrayListens);

return JsonConvert.SerializeObject(new { actions = JArraySays });

yep this works. ``` {"actions":[{"say":"Hi, how can I help you today?"},{"listen":false}]} ```

weichch · Accepted Answer · 2020-03-30 03:56:51Z

1

Since your class is already called Actions, you could do something like this:

[Serializable]
public class Actions : ISerializable
{
    public string say { get; set; }
    public bool? listen { get; set; }

    public void GetObjectData(SerializationInfo info, StreamingContext context)
    {
        info.AddValue("actions", new object[] { new { say }, new { listen } });
    }
}

Usage:

var actions = new Actions();
actions.say = say;
actions.listen = listen;
var json = JsonConvert.SerializeObject(actions);

edited Mar 30, 2020 at 3:56

answered Mar 29, 2020 at 10:36

weichch

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2 Comments

Max Over a year ago

Hi, implemented this, but it looks like it just gives output as mentioned in the question.

weichch Over a year ago

@KiranP. Sorry my bad, I forgot that [Serializable] attribute. Now updated. Also created a .net fiddle dotnetfiddle.net/lxxWKO

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