TypeError while using subprocess

Question

I am using subprocess to capture output of another python file into the current one.Here is my code-

    import subprocess
    a= subprocess.run('python3 try1.py', capture_output=True,shell=True)

But when I run the code, I get an error-

<pre>Traceback (most recent call last):
  File &quot;test2.py&quot;, line 4, in &lt;module&gt;
    c1= subprocess.run(&apos;python3 test2.py&apos;, capture_output=True,shell=True)
  File &quot;/usr/lib/python3.6/subprocess.py&quot;, line 423, in run
    with Popen(*popenargs, **kwargs) as process:
TypeError: __init__() got an unexpected keyword argument &apos;capture_output&apos;
</pre>

I am running Python 3.6.8. Also, a file named subprocess.py doesn't exist on my PC. It used to, but I deleted it. Thanks for all help!

If you read the docs, at the very end of a function description there are changes described depending on Python version. In this case the parameter was added in Python 3.7. — Michael Butscher
– Michael Butscher, Commented Mar 28, 2020 at 14:56
You need to put the args in a list like: ['python3', 'try1.py']. — Roy Levy
– Roy Levy, Commented Mar 28, 2020 at 14:57

Rahul P · Accepted Answer · 2020-03-28 14:56:23Z

4

The capture_output parameter does not exist in Python 3.6 which is what you are using. Hence the error. You can use this instead:

subprocess.check_output(['python3', 'try1.py'])

answered Mar 28, 2020 at 14:56

Rahul P

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