How can I generate random number in specific range in Android? [duplicate]

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How do I generate random integers within a specific range in Java? (59 answers)

How can I get a random number in Kotlin? (25 answers)

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I want to generate random number in a specific range. (Ex. Range Between 65 to 80)

I try as per below code, but it is not very use full. It also returns the value greater then max. value(greater then 80).

Random r = new Random();
int i1 = (r.nextInt(80) + 65);

How can I generate random number between a range?

You can write val randomNumber = (min..max).random() where min and max are the edges of the specified range. Refer Kotlin – Generate a Random Number in specific Range — arjun
– arjun, Commented Jun 14, 2023 at 9:48

Mr. Polywhirl · Accepted Answer · 2014-02-14 02:22:10Z

525

Random r = new Random();
int i1 = r.nextInt(80 - 65) + 65;

This gives a random integer between 65 (inclusive) and 80 (exclusive), one of 65,66,...,78,79.

edited Feb 14, 2014 at 2:22

Mr. Polywhirl

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answered May 17, 2011 at 10:29

Ishtar

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7 Comments

Kirill Kulakov Over a year ago

it won't work for negative numbers

Allison Over a year ago

If you need a negative number, use this and multiply by -1. You need a float, I think.

TomeeNS Over a year ago

@Sirens: He could even generate two more numbers, then count differente between them (it can be negative or positive number ;)), and finaly multiply the original random number ;)

Alecs Over a year ago

simpler as possible: int myRandomInt = new Random().nextInt(80 - 65) + 65;

Saik Caskey Over a year ago

I've been writing Java in one way or another for about 8 years and I still copy and paste this code whenever I need it, cheers 👍

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Dumbo · Accepted Answer · 2015-12-18 23:10:56Z

308

int min = 65;
int max = 80;

Random r = new Random();
int i1 = r.nextInt(max - min + 1) + min;

Note that nextInt(int max) returns an int between 0 inclusive and max exclusive. Hence the +1.

edited Dec 18, 2015 at 23:10

Dumbo

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answered May 17, 2011 at 10:29

Vivien Barousse

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