Sort javascript array of objects by property value and reorder by condition

Question

I have an array of objects Like :

    var newArray = [
      {value : "P1"},
      {value : "P2/S2"},
      {value : "P2"},
      {value : "P1"},
      {value : "P1/S2"},
      {value : "P1/S3"},
      {value : "P2/S1"},
      {value : "P1/S3"},
      {value : "P2/S2"},
      {value : "P1"},
      {value : "P2"},
      {value : "P3"}
    ];
    
    function compare( a, b ) {
      if ( a.value < b.value ){
        return -1;
      }
      if ( a.value > b.value ){
        return 1;
      }
      return 0;
    }
    
    newArray.sort( compare );
    console.log(newArray);

[{"value":"P1"},{"value":"P1"},{"value":"P1"},{"value":"P1/S2"},{"value":"P1/S3"},{"value":"P1/S3"},{"value":"P2"},{"value":"P2"},{"value":"P2/S1"},{"value":"P2/S2"},{"value":"P2/S2"},{"value":"P3"}]

But here i have a rearrangement in sorting if there is no S value after P value. P value should be low priority if there is no S value. I am expecting a result like this :

[{"value":"P1/S2"},{"value":"P1/S3"},{"value":"P1/S3"},{"value":"P1"},{"value":"P1"},{"value":"P1"},{"value":"P2/S1"},{"value":"P2/S2"},{"value":"P2/S2"},{"value":"P2"},{"value":"P2"},{"value":"P3"}]

Nina Scholz · Accepted Answer · 2019-12-19 09:53:57Z

3

You could add a suffix and sort smaller strings to the bottom.

function compare({ value: a }, { value: b }) {
    a += 'ZZZ';
    b += 'ZZZ';
    return a > b || -(a < b);
}

var array = [{ value: "P1" }, { value: "P2/S2" }, { value: "P2" }, { value: "P1" }, { value: "P1/S2" }, { value: "P1/S3" }, { value: "P2/S1" }, { value: "P1/S3" }, { value: "P2/S2" }, { value: "P1" }, { value: "P2" }, { value: "P3" }];
   
array.sort(compare);

console.log(array);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Dec 19, 2019 at 9:53

Nina Scholz

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Francesco · Accepted Answer · 2019-12-19 10:41:30Z

0

Maybe computing values weight? For example:

function computeWeight(str) {
  var weight = 0;
  for (var i = str.length-1; i >= 0; i--) {
    weight = weight + (str.charCodeAt(i) * Math.pow(10, i));
  }
  return weight;
}

this way longer strings will have a greater weight than the smaller ones because they have more symbols. Then you can use that function in your compare.

answered Dec 19, 2019 at 10:41

Francesco

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