In your function signature, you are telling the compiler that lenghtchar() expects a pointer to character strings, or **char in other words.
What you really want to do is to change your function from int lengthchar(char *array1[]) to int lengthchar(char array1[]) or int lengthchar(char *array1). This is a bit tricky since in C, you can address an array by using the address of its first element (aka, by using pointer to its first item).
Expert C Programming has a dedicated chapter on this topic.
Now, coming to your lengthchar() function, I would do some refactoring to eliminate the variable a and use a while loop instead. I have also included another alternative implementation that relies on pointer arithmetic (more fun to me :) )
Note also that I used fgets() instead of gets() which is considered deprecated since it does not do any bounds checking.
#include <stdio.h>
#include <stdlib.h>
#define max 100
/*
* returns the lenght of the string excluding the terminating
* NULL character
*/
int lengthchar(char *array1) {
int x = 0;
while (*array1++)
x++;
return x-1;
}
int lengthchar1(char *array1){
char *p;
for (p = array1; *p; p++)
;
return p - array1 - 1; /* -1 for \0 */
}
int main() {
char arr1[max];
int length;
printf("Enter string\n");
fgets(arr1, max, stdin);
length = lengthchar(arr1);
printf("Length=%d", length);
return 0;
}
char *array1orchar array1[]. BTW, the variableaisn't doing anything useful and should be removed.for(;*(array1++)!='\0';)whileloop:while (array[x]) x++; return x;