Parse columns into separate arrays

Question

I have a space-delimited file:

Pool    Library Name    Email   Subject
Finland lib1    Guru    [email protected],[email protected]   Finland Media Rotation
Tucson  lib2    Albert  [email protected] Tucson Media Rotation
Vancouver   lib3    Jeff    [email protected] Vancouver Media Rotation

I want to parse the columns into arrays like:

declare -a Pool=(Finland Tucson Vancouver)
declare -a Library=(lib1 lib2 lib3)
declare -a Name=(Guru Albert Jeff)
declare -a Email=("[email protected],[email protected]" [email protected] [email protected])

My code is:

column=1
for arrayname in Pool Library; do
     mapfile -t "$arrayname" < <(awk "NR > 1 {print \$$column}" file.txt)
     ((column++))
done

But it's failing in case of multiple items like in Email.

@GURUSINGH, Will Name field have spaces in between them or any other field? — RavinderSingh13
– RavinderSingh13, Commented Nov 30, 2019 at 15:25
If there are multiple names in EMAIL then it will be a comma in between them. — GURU SINGH
– GURU SINGH, Commented Nov 30, 2019 at 15:30
@GURUSINGH, No, I meant for Name column. I got the email part, how about Name column? — RavinderSingh13
– RavinderSingh13, Commented Nov 30, 2019 at 15:31
your project will be much easier to manage if you can use either tab-char or | as the field separator for your data. Good luck. — shellter
– shellter, Commented Nov 30, 2019 at 15:45
You are likely to get better feedback if you will clarify what is failing. 'Failing in case of multiple items` is not clear. Splitting the problem over multiple posts unlikely to get any complete answer: stackoverflow.com/questions/58998007/…, stackoverflow.com/questions/59021512/… — dash-o
– dash-o, Commented Dec 1, 2019 at 0:36

RavinderSingh13 · Accepted Answer · 2019-11-30 16:27:39Z

3

Could you please try following.

awk -v s1="\"" '
FNR==1{
  for(i=1;i<=NF;i++){
    header[i]=$i
  }
  val=length(header)
  next
}
{
  match($0,/.*\.com +/)
  string=substr($0,RSTART,RLENGTH)
  num=split(string,array," ")
  for(i=1;i<=num;i++){
    values[i]=(values[i]?values[i] OFS:"")s1 array[i] s1
  }
  values[num+1]=(values[num+1]?values[num+1] OFS:"")substr($0,RSTART+RLENGTH)
  delete array
}
END{
  for(i=1;i<=val;i++){
    print "declare -a " header[i] "=(" values[i]")"
  }
}
'  Input_file

This will print the array creation commands on terminal, you could use the as per your need.

answered Nov 30, 2019 at 16:27

RavinderSingh13

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2 Comments

GURU SINGH Over a year ago

thanks for your help. your code works like charm.I need one little help too, that now how to pass these arguments to my script.

RavinderSingh13 Over a year ago

@GURUSINGH, Np. Please have 1 question and 1 thread only, you could open a new thread with your EFFORTS which you have put in order to solve your own problem, cheers and happy learning.

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