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I would like to learn how to code this.

Here is how I want it to look

Do you want strawberry ice cream? (y:n) n
Do you want chocolate ice cream?  (y:n) y
Do you want mint ice cream? (y:n) n
Do you want vanilla ice cream? (y:n) y

then the output would be: Here is your ice cream. or if you put N to all, You did not say yes to any. Or with the else statement: I didn't get that, try again.

Any help is very much appreciated, thank you.

My test script:

def kind(chosenIce):
      chosenIce=input("Do you want a ice cream (y:n) ")
      if chosenIce1 == 'y':
          ice1 = print("message")
      if chosenIce2 == 'y':
          ice2 = print("message")
      if chosenIce1 == 'n':
          ice1 = 0
      if chosenIce2 == 'n':
          ice2 = 0
      else:
         print("Sorry, I did not get that. Try again.")
kind(chosenIce)
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2
  • 1
    A few examples: Why are you overriding the argument chosenIce in the first line of the function? Where do chosenIce1 and chosenIce2 come from? What is supposed to happen from ice1 = print("message")? Commented Nov 23, 2019 at 8:28
  • A very similar problem was posted here: stackoverflow.com/q/59005266/2745495. Instead of ice cream, it’s about cars. But the input format is the same. Commented Nov 23, 2019 at 9:10

4 Answers 4

Reset to default
1

As some fellows said, you have to use input and loop (i.e for loop or while loop) to achieve your goal. By reading your post and the comments, it seems you are really a newbie in Python. So, below, I give you a basic workflow that does something like your needs. There are many ways to achieve your goals. You can look at my workflow for inspiration.

Here is the code:

def kind(ices_cream):
    choices = []
    for ice in ices_cream:
        chosenIce = input('Do you want "{}" ice cream (y:n) '.format(ice))
        if chosenIce == 'y':
            choices.append(ice)
        elif chosenIce == 'n':
            print("You refuse ", ice)
        else:
            print("Sorry, I did not get that. Try again.")

    if len(choices):
        print("\n", "You buy", ' and '.join(choices))
    else:
        print("\n", "You buy nothing!")

if __name__ == "__main__":
    ices_cream = ["Chocolate", "Strawberry", "Mint", "Vanilla"]
    kind(ices_cream)

Outputs: It is an example

Do you want "Chocolate" ice cream (y:n) y
Do you want "Strawberry" ice cream (y:n) n
You refuse  Strawberry
Do you want "Mint" ice cream (y:n) y
Do you want "Vanilla" ice cream (y:n) n
You refuse  Vanilla

 You buy Chocolate and Mint

NB: You can add a loop while to force the user to input the characters y or n. Also, you can add exception handling if you want to do a good job.

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3 Comments

This is a very helpful basic code, thank you for taking the time. I am super new to Python. I'd like to know is {} for choices=[] that links to ices_cream = ["Chocolate", "etc"] at the bottom?
ices_cream = ["Chocolate", "Strawberry", "Mint", "Vanilla"] is like the menu of the restaurant. So, in the logic, you pass the menu to a function that manage the customer order.
In the function def kind(ices_cream): ..., the list choices contains the client order. So, you will use this list later to print later something like You buy Chocolate and Mint. Keep in mind: there are many ways to achieve your goal.
1

Regarding only what you want in this problem, you will use the function input. The way to use it is this:

strawberryIceCream=input('Do you want strawberry ice cream? (y/n)')

and so on, so forth with the other options as well. Remember to store each option in either a different variable or, better IMHO, in a set or tuple.

Further info on input

However, the comments' on your question are accurate and on point. This is why I mentioned that this answer will answer only your question. Nothing more, nothing less.

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3 Comments

I know how to do input, along with if, elif and else, I just do not know how to do the questions with the extra Y and N's. In my original code, I had if chosenIce1 == 'Y', if chosenIce2 == 'Y', and then the same thing with N, with the ice1 = 0 under it.
This is a very different matter, which you do not address in your question. You only wanted to know how to get user input, and I told you how to. If you want an answer to this problem, please make another question.
@BeR see my answer.
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listQue=["Do you want strawberry ice cream?","Do you want chocolate ice cream?","Do 
you want mint ice cream?","Do you want vanilla ice cream?"]

flag=False
for que in listQue:
    ans=input(que)
    if(ans=='Y'):
        res=que.split()
        print("Here is your"," ".join(res[3:6]).rstrip('?'))
        flag=True
   else:
        pass


if(flag==False):
    print("Ohhh sorry you didn't choose anything")
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Comments

0

In python 3 you can use input() (examples here) and in python 2 raw_input() (examples here). You need to code the rest yourself using for-loops... etc.

Example:

choices = []

x1 = input('Do you want strawberry ice cream? (y/n)')

choices.append(x1)  # store the choice for each question here so you can use it later for
                # selection criteria process. Store x2 at choices[1], etc.

for choice in choices:
    if choice in ['y', 'Y', 'yes', YES']:
        print ('User does like an iscream')
    else:
        print ('User no fan of the cold treat')
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5 Comments

Thank you, this is very simple and is super easy to understand now.
Your welcome. As you're also new to SO.. you can upvote more than one answer if more answer did help you out to get what you want. I saw some of the answer are beyond beginners level therefor I kept it small and easy so you can play with it and learn easily.
@quamrana as OP stated to be a beginner I've chosen for a simple entry answer. No use to come-up with defs and classes in this case.
I’m sorry BeR, I’m not going to write code for you, now that you have removed yours from the question.
@quamrana if you found a typo... just fix it. ATM at a simple PC without language editor to run it. And I see what you ment with "removed code". Fixed.

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