How to find the presence of element in bash array [duplicate]

Question

Possible Duplicate:
Bash: check if an array contains a value

i have list like

list = ['pic1','pic2','pic3'];

i am in array like

for a in /dir/star
if(a is in list then skip the loop)
do
echo "hello";
done

I want to skip the loop if element is in list

The list = ['pic1','pic2','pic3']; notation is not an assignment in bash; it is an invocation of the command list with two arguments, one of which is an equals sign and the other of which is "[pic1,pic2,pic3]" when the command sees it. — Jonathan Leffler
– Jonathan Leffler, Commented May 3, 2011 at 14:45
I agree with Jonathan. Please either fix this question or delete it. — shellter
– shellter, Commented May 3, 2011 at 21:55

l0b0 · Accepted Answer · 2011-05-03 14:37:41Z

0

for path in /dir/*
do
    for val in pic1 pic2 pic3
    do
        if [ "$(basename -- "$path")x" = "${val}x" ]
        then
            continue 2 # Next path
        fi
    done
    # No match, do whatever you want
done

If you want to end processing completely after finding the first match, just replace continue with break.

answered May 3, 2011 at 14:37

l0b0

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