Getting the last number from a FOR loop

Question

I have this code:

def LCM(minN,maxN):

    count = 1
    for i in range(count,(maxN*count)+1):
        print(minN*count)
        count = count + 1

And if I call it like so: LCM(5,7) its gonna give me the numbers:

5
10
15
20
25
30
35

How could I make the program output (instead of all the numbers) just the last one, in this example: 35

I tried looking it up in the other topics but none were of any help.

Answer 1

Move the print statement outside the for loop?

def LCM(minN,maxN):
    count = 1
    for i in range(count,(maxN*count)):
        count = count + 1
    print(minN*count)

---

LCM(5,7)
# 35

Answer 2

you can simplify your LCM method:

def LCM(minN, maxN):
    print(minN * maxN)

LCM(5,7)

output:

35

Answer 3

You can use a list:

def LCM(minN,maxN):

    count = 1
    results = []
    for i in range(count,(maxN*count)+1):
        results.append(minN*count)
        count = count + 1
    print(results[-1]) # print the last elements of the list.

So, when You call LCM(5, 7), You will get 35.

Answer 4

def LCM(minN,maxN):
    count = 1
    for i in range(count,(maxN*count)+1):
        count = count + 1
    else:
      print(minN*(count-1))

Answer 5

Let's do some simplification. Here's your original code:

def LCM(minN,maxN):
    count = 1
    for i in range(count,(maxN*count)+1):
        print(minN*count)
        count = count + 1

count could be removed from this:

def LCM(minN,maxN):
    for i in range(1, maxN+1):
        print(minN*i)

Now, you want to print just the last value of this sequence. The last value of i will be maxN:

def LCM(minN,maxN):
    for i in range(1, maxN+1):
        pass
    print(minN * maxN)

Or simply:

def LCM(minN,maxN):
    print(minN * maxN)