How do you sort a list by elemant thats a tuple? Let say below is the list LL. I want to sort ID2 -- LL[1] which is a tuple as asc. How would I do it.
Id, Id2 CCC
A123 A120 '2011-03'
LL= A133 A123 '2011-03'
D123 D120 '2011-04'
D140 D123 '2011-04'
Have a look at http://wiki.python.org/moin/HowTo/Sorting/
sorted(LL, key=itemgetter(1)) might do what you want.
Please note that you have to from operator import itemgetter to get the itemgetter function.
In [1]: LL = (('A123', 'A120', '2011-03'), ('A133', 'A123', '2011-03'), ('D123', 'D120', '2011-04'), ('D140', 'D123', '2011-04'))
In [2]: from operator import itemgetter
In [3]: sorted(LL, key=itemgetter(1))
Out[3]:
[('A123', 'A120', '2011-03'),
('A133', 'A123', '2011-03'),
('D123', 'D120', '2011-04'),
('D140', 'D123', '2011-04')]
key=itemgetter(1) will make sorted() fetch the item with index 1 from each element in LL. Please actually read the page I linked to, it explains it: wiki.python.org/moin/HowTo/Sorting/#Operator_Module_FunctionsYou can go for:
LL.sort(key=lambda x:x[1])
Where 1 is the index of the element of the tupple.
itemgetter(1) from the operator module. Otherwise a python function needs to be called for every item (the operator functions are written in C if you are using the default CPython implementation)
ID2 -- LL[1] which is a tuple as asc- what?