How to parse json without additional class?

Question

I have json with only one type which including some properties

{"Agreement":{"agreementId":"1","CreatedOn":"2016-09-02T09:25:05","ModifiedOn":"2019-06-30T23:30:00.173"}}

I`m using Newtonsoft JsonConvert.

Is it possible to parse it to model like this?

public class Agreement
{
public int Id {get; set;}
public DateTime CreatedOn {get; set;}
public DateTime ModifiedOn {get; set;}
}

Now i must declare additional class, which contains this type

public class AgreementAdditional
{
public Agreement Agreement {get; set;}
}

May be its duplicate, but i cant google it correctly

NotFound · Accepted Answer · 2019-08-15 11:47:14Z

2

You could use the JObject class.

var json = File.ReadAllText("json1.json");
var example = JObject.Parse(json)["Agreement"].ToObject<Agreement>();

Although I see nothing wrong with the AgreementAdditional class as that's the exact format of your input.

answered Aug 15, 2019 at 11:47

NotFound

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Comments

Renan Araújo · Accepted Answer · 2019-08-15 12:06:15Z

2

You can use dynamic.

Using Newtonsoft you can do it like this:

dynamic result = JsonConvert.DeserializeObject(json);

And using JObject you can do it like this:

dynamic result = JObject.Parse(json);

To use the dynamic object, use it using the same names on the json file.

result.Agreement.agreementId
...

However, creating a class is still a better choice for code maintenance.

answered Aug 15, 2019 at 11:59

Renan Araújo

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I think if OP goes this route then the statement would be agreement.Agreement...

dynamic type is not what i want. I will use two classes, thank you for advice!