Using ForEach with a string array - [String] has no member 'identified'

Question

I'm using Xcode 11 beta 5 and what I had it doesn't work anymore. This is my code:

struct ModeView : View {
  @EnvironmentObject var state: IntentionState

  var body: some View {
      Picker(selection: $state.selection, label: Text("")) {
        ForEach(state.modes.identified(by: \.self)) { mode in
          Text(mode)
        }
      }.pickerStyle(SegmentedPickerStyle())
  }
}

The error is in the line ForEach(uistate.modes.identified(by: \.self)) { mode in and it says:

Value of type '[String]' has no member 'identified'

When I was using Xcode 11 beta 4 it worked perfectly. The question now is how to use ForEach with an array string in Xcode beta 5

backslash-f · Accepted Answer · 2019-08-01 18:27:17Z

11

ForEach syntax changed a little bit in Beta 5.

Have you tried:

ForEach(state.modes, id: \.self) { mode in
    Text(mode)
}

answered Aug 1, 2019 at 18:27

backslash-f

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1 Comment

fdelafuente Over a year ago

Thanks, that's the solution

Sharad Paghadal · Accepted Answer · 2019-08-01 17:52:08Z

1

As per the apple release note, it's known issue from their end. We have to wait for another release.

https://developer.apple.com/documentation/ios_ipados_release_notes/ios_ipados_13_beta_5_release_notes

answered Aug 1, 2019 at 17:52

Sharad Paghadal

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2 Comments

fdelafuente Over a year ago

What would it be a complex expression? In my case, what I have in the closure seems to be very simple

Alexander Over a year ago

@fdelafuente What happens if you try extracting that expression to a separate variable, and pass the variable to ForEach?

Michael Salmon · Accepted Answer · 2019-08-01 18:32:51Z

1

The identified(by:) method has been deprecated, the correct syntax is now:

init(Data, id: KeyPath<Data.Element, ID>, content: (Data.Element) -> Content)

or after moving the content into a closure :

ForEach(state.modes, id: \.self) { mode in Text(mode) }

answered Aug 1, 2019 at 18:32

Michael Salmon

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Comments

aturan23 · Accepted Answer · 2020-06-28 12:07:56Z

0

let suppose you have a name array like this:

let names = ["mike","Jack","jill"]

ForEach(names, id: \.self) { Text($0) }

Text($0) - this will print all elements from your names array.

Note:

Use backslashsign.self instead .self, somehow backslash sign is not working here

edited Jun 28, 2020 at 12:07

aturan23

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answered Sep 17, 2019 at 2:42

Amit Thakur

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