how to iterate through the link in selenium/python

Question

In web page i have n number of links ie the links displayed are random there may be one link or there be five links.I have written code in way that it will open first link in a new tab and do some function.The problem is i don't how to do the same if there are more links . is it possible to iterate or any other way to handle this

Changerequest is the link that is present in the webpage

Sourcecontrol = driver.find_element_by_xpath('//li[@class="menu-item"]/a[contains(.,"Source Control")]')
   Sourcecontrol.click();
   Changerequest=driver.find_element_by_xpath( '//td[@class="confluenceTd"]/a[contains(.,"Change: ")]');
   testvalue = Changerequest.get_attribute('href')
   driver.execute_script("window.open(arguments[0])",testvalue)
   window_after = driver.window_handles[1]
   driver.switch_to_window(window_after)

sample HTML of the links

<div class="flooded">
                    <div class="table-wrap">
<table class="confluenceTable"><tbody>
<tr>
<td class="confluenceTd"><a href="link" class="external-link" rel="nofollow" title="Follow link">Change: 1111</a></td>
<td class="confluenceTd">date</td>
</tr>
<tr>
<td class="confluenceTd"><a href="Link" rel="nofollow" title="Follow link">Change: 2222</a></td>
<td class="confluenceTd">date</td>
</tr>
<tr>
<td class="confluenceTd"><a href="link" class="external-link" rel="nofollow" title="Follow link">Change: 33333</a></td>
<td class="confluenceTd">date</td>
</tr>
<tr>
<td class="confluenceTd"><a href="link" class="external-link" rel="nofollow" title="Follow link">Change: 44444</a></td>
<td class="confluenceTd">date</td>
</tr>
</tbody></table>
</div>

                </div>

KunduK · Accepted Answer · 2019-07-30 13:29:41Z

Try the following code.

from selenium import webdriver
driver=webdriver.Chrome()
driver.get("url")
for item in driver.find_elements_by_css_selector('td.confluenceTd a'):
    link = item.get_attribute('href')
    window_before = driver.window_handles[0]
    driver.execute_script("window.open(arguments[0])",link)
    window_after = driver.window_handles[-1]
    driver.switch_to.window(window_after)
    #Perform some action
    #
    print(driver.current_url)
    #
    driver.switch_to.window(window_before)

OR

for item in driver.find_elements_by_xpath("//td[@class='confluenceTd']//a[contains(.,'Change:')]"):
    link = item.get_attribute('href')
    window_before = driver.window_handles[0]
    driver.execute_script("window.open(arguments[0])",link)
    window_after = driver.window_handles[-1]
    driver.switch_to.window(window_after)
    #Perform some action
    #
    print(driver.current_url)
    #
    driver.switch_to.window(window_before)

Moshe Slavin · Accepted Answer · 2019-07-30 14:01:10Z

0

You can use find_elements with s to get all the elements...

Your loop should look something like:

for i in driver.find_elements_by_xpath( '//td[@class="confluenceTd"]/a'):
    testvalue = i.get_attribute('href')
    driver.execute_script("window.open(arguments[0])",testvalue)
    window_after = driver.window_handles[-1]
    driver.switch_to_window(window_after)
    # do something...
    driver.switch_to.default_content()

edited Jul 30, 2019 at 14:01

answered Jul 30, 2019 at 12:50

Moshe Slavin

5,2445 gold badges27 silver badges40 bronze badges

2 Comments

saranya Over a year ago

:does it not click the same link when we follow the above method.please correct me if i am wrong

Moshe Slavin Over a year ago

@saranya I had a typo with the window_handles... [1] is should be [-1]...

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