Why is this for loop throwing a TypeError?

Question

I am writing the method to draw a full circle in a numpy array of pixels, and I just don't understand why I am getting a TypeError. I apologize in advanced - I am a new Python programmer who recently switched from Java and I am still having trouble with all of this "lack-of-defining-variable-data-type-ing".

class Image:

    def drawCircle(self, centerX, centerY, radius):
        sin45 = 0.70710678118                                               
        distance = radius/(2*sin45)
        for i in range(radius,distance,-1.0): ####This is the error line####
            j = math.sqrt(r*r - i*i)
            for k in range(-j, j, 1):
                self.writePixel(self.centerX - k, self.enterY + i)
                self.writePixel(self.centerX - k, self.enterY - i)
                self.writePixel(self.centerX + i, self.enterY + i)
                self.writePixel(self.centerX - i, self.enterY - i)

'''Testing the code'''
obj = Image()
obj.drawCircle(35.0, 35.0, 35.0)

This code may be filled with other errors, but as of right now I am stumped on "TypeError: 'float' object cannot be interpreted as an integer". Also, for the sake of saving space I have left the definition for writePixel() out, but just assume that it works. Thanks!

range cannot accept float, radius and distance might be floats — Khalil Al Hooti
– Khalil Al Hooti, Commented Jul 19, 2019 at 19:15

flashy · Accepted Answer · 2019-07-19 19:14:22Z

2

Change:

for i in range(radius,distance,-1.0):

To:

for i in range(int(radius),int(distance),int(-1.0)):
#or
for i in range(int(radius),int(distance),-1):

It should be noted that this will round those numbers down so if you need the precision of a decimal you should consider using a linspace from numpy instead of a range.

Also this will only fix the TypeError, not saying this will fix other issues

edited Jul 19, 2019 at 19:14

flashy

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answered Jul 19, 2019 at 19:10

Jmonsky

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1 Comment

Green Cloak Guy Over a year ago

This is almost certainly what's causing the error. Worth noting, no need to bring numpy into it - if you need to round to the nearest whole number (and not just strictly down) you can probably just use the built-in round() function instead of int()

Krishna Rao · Accepted Answer · 2019-07-19 19:15:37Z

0

The third parameter in range function should be integer not a float. I guess that is causing issue. Please try using -1 instead of -1.0 , also convert radius and distance to int.

edited Jul 19, 2019 at 19:15

answered Jul 19, 2019 at 19:12

Krishna Rao

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Comments

Shreyas Khadke · Accepted Answer · 2019-07-19 19:13:42Z

-1

In your code your are using variable r without defining it.

Try using int(math.sqrt())

edited Jul 19, 2019 at 19:13

answered Jul 19, 2019 at 19:10

Shreyas Khadke

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2 Comments

John Gordon Over a year ago

That wouldn't be a TypeError.

Shreyas Khadke Over a year ago

Also check for math.sqrt statement it will return float so use int(math.sqrt())

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