Return the bash file code at the end of execution in php [duplicate]

Question

I have used a bash file in a php file. (Require/Include) After that when i want to run the bash file, but not want code will be returned. Result is coming at the end. But the unnecessary codes are coming.

<?php
require_once("shapemorph");
ob_start();
$imageFile2 = 'one-car.jpg';
$imageFile1 = 'two-car.jpg';
shell_exec('./shapemorph -d 10 -p 100 -r "73,56 57,68" '.$imageFile2.' '.$imageFile2.' testfy.gif');
ob_end_flush();
exit;
?>

I have used ob_start() for that also. But still the codes are coming.

I do not want the code to be returned.

You could look at this thread too stackoverflow.com/questions/2292847/… — John Carr
– John Carr, Commented Apr 24, 2019 at 14:22

leo Stahl · Accepted Answer · 2019-04-24 13:51:17Z

1

You can Just return them to /dev/null if your using Linux

answered Apr 24, 2019 at 13:51

leo Stahl

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4 Comments

Ranjit Pradhan Over a year ago

Thanks for reply. But this code should work in server. I am unknown about the server configuration.

leo Stahl Over a year ago

you could also redirect the output in a file and remove it as last operation of your script like : myscript >> trash.txt

Ranjit Pradhan Over a year ago

Are you telling in the bash file ?

Jay Blanchard Over a year ago

It's not hard to earn enough rep to make comments.

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