What does the error "Name Error: name is not defined" mean in this code [duplicate]

Question

Consider the following code:

def distancias(altitudes,lado,p1,p2):
    p1=(r1,c1)
    p2=(r2,c2)
    a1=altitudes[p1]
    a2=altitudes[p2]
    d=math.sqrt((lado(r1-r2)**2)+(lado(c1-c2)**2)+(a1-a2)**2)
    return d

Altitudes is a matrix and p1 and p2 are elements of the matrix.

When I call the function distancias(teste, 20, (2, 0), (3, 1)), it is giving me this error:

Traceback (most recent call last):

  File "<ipython-input-11-6c6a4bb1ff77>", line 1, in <module>
    distancias(teste, 20, (2, 0), (3, 1))

  File "C...", line 5, in distancias
    p1=(r1,c1)

NameError: name 'r1' is not defined

    "Name Error: name is not defined".

(I want to understand it better as i am new to Python)

you have not posted all the code (that error can't have come from this snippet!) — Joe Iddon
– Joe Iddon, Commented Apr 20, 2019 at 19:23
Unless "name" is actually r1 and you're paraphrasing. Post the actual error. — Carcigenicate
– Carcigenicate, Commented Apr 20, 2019 at 19:27
Welcome to StackOverflow. To help you with your error, you need to show us a complete code snippet that shows that error when we run that code. Please read and follow How to create a Minimal, Complete, and Verifiable example. — Rory Daulton
– Rory Daulton, Commented Apr 20, 2019 at 19:29
always put full error message (Traceback) in question (as text, not screenshot). There are other useful information. — furas
– furas, Commented Apr 20, 2019 at 19:35

Rajdeep Karetha · Accepted Answer · 2019-04-20 19:48:05Z

0

hello this is because "r1,c1,r2,c2" are not the definition of function distancias. so use should define these variable before using them. Actually you should post the full code for better understanding of others.but if you this piece to work.you should change something like this.

     `def distancias(altitudes,lado,r1,r2,c1,c2):
      p1=(r1,c1)
      p2=(r2,c2)
      a1=altitudes[p1]
      a2=altitudes[p2]
      d=math.sqrt((lado(r1-r2)**2)+(lado(c1-c2)**2)+(a1-a2)**2)
      return d`

answered Apr 20, 2019 at 19:48

Rajdeep Karetha

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1 Comment

Alec Over a year ago

Um, no. Functions can access values not fed as arguments to it

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