How to check whether two three dimensional numpy arrays are the same? [duplicate]

Question

I have a numpy array with shape (1,x,1) and the second one also with shape (1,x,1). I wonder how can I check whether they are the same? Examples:

1. First:

[[[ 2]
  [ 3]
  [ 4]
  [ 5]
  [ 6]
  [ 7]
  [ 8]
  [ 9]
  [ 4]
  [ 6]
  [10]]]

Second:

[[[ 2]
  [ 3]
  [ 4]
  [ 5]
  [ 6]
  [ 7]
  [ 8]
  [ 9]
  [ 4]
  [ 6]
  [10]]]

Response: True

2.

First:

[[[ 2]
  [ 3]
  [ 4]
  [ 5]
  [ 6]
  [ 7]
  [ 8]
  [ 9]
  [ 4]]]

Second:

[[[ 1]
  [ 2]
  [ 3]
  [ 5]
  [ 6]
  [ 2]
  [ 8]
  [ 3]
  [ 5]]]

Response: False

np.allclose is easy to use, and better if the arrays are floats. — hpaulj
– hpaulj, Commented Apr 13, 2019 at 17:05

Sebastian Dengler · Accepted Answer · 2019-04-13 17:00:38Z

0

There is already a SO question with that topic and a good answer by @Juh_ link.

The solution:

(A==B).all()

answered Apr 13, 2019 at 17:00

Sebastian Dengler

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2 Comments

np.array_equal will work, too?

Yes it should, it's also mentioned in the answer :)