Is there an easy way to convert an array of boolean values into 8-bit hexadecimal equivlents? For example, if I have
bool[] BoolArray = new bool[] { true,false,true,true,false,false,false,true };
If true values=1 and false values=0 then I'd like a method or function that would convert the above array to 0xB1 (10110001).
Does there exist such a function or method to do this? I am using C#, by the way.
Yes, you can use the BitArray class. Something like this should do it:
BitArray arr = new BitArray(BoolArray);
byte[] data = new byte[1];
arr.CopyTo(data, 0);
If by "8-bit hexadecimal" you mean the string representation, you can use the BitConverter class for that:
string hex = BitConverter.ToString(data);
How about
static int BoolArrayToInt(bool[] arr)
{
if (arr.Length > 31)
throw new ApplicationException("too many elements to be converted to a single int");
int val = 0;
for (int i = 0; i < arr.Length; ++i)
if (arr[i]) val |= 1 << i;
return val;
}
static string ToHexStr(int i) { return i.ToString("X8"); }
note: an editor remarked that arr[0] is the LSB but he expected MSB. This is an API consideration, if you prefer your LSB to be at arr[length-1] just reverse the array before passing to that function.
The Binary part can be achieved through this method:
bool[] boolArray = {true, false, true} will give 101:
int BoolArrayToInt(bool[] bArray)
{
char[] caseChar = new char[bArray.Length];
for(int i = 0; i < bArray.Length; i++)
{
if (bArray[i] == true)
{
caseChar[i] = '1';
}
else
{
caseChar[i] = '0';
}
}
string caseString = new string(caseChar);
int caseNum = System.Convert.ToInt32(caseString);
return caseNum;
}
