JavaScript string .replace for URL

Question

I scrape sites for a database with a chrome extension, need assitance with a JavaScript Clean up function

e.g

https://www.alibaba.com/product-detail/_60789694386.html?spm=a2700.galleryofferlist.normalList.1.5be41470uWBNGm&s=p

my target output is:

_60789694386.html

everything past .html needs to be removed, but since it is diffrent in each URL - i'm lost

the output is in a .csv file, in which i run a JavaScript to clean up the data.

   this.values[8] = this.values[8].replace("https://www.alibaba.com/product-detail/","");

this.values[8] is how i target the column in the script. (Column 8 holds the URL)

you could split at ? and get the first bit. yourString.split('?')[0] ? — iacobalin
– iacobalin, Commented Mar 15, 2019 at 13:41
This could be helpful [Remove query string] [stackoverflow.com/remove-querystring-from-url ](stackoverflow.com/questions/2540969/remove-querystring-from-url) — ejaz
– ejaz, Commented Mar 15, 2019 at 13:49

Mickael B. · Accepted Answer · 2020-01-16 17:25:29Z

3

Well, you can use split.

var final = this.values[8].split('.html')[0]

split gives you an array of items split by a string, in your case'.html', then you take the first one.

edited Jan 16, 2020 at 17:25

Mickael B.

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answered Mar 15, 2019 at 13:42

Raul Rene

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Comments

Gwyn Rees · Accepted Answer · 2019-03-15 13:42:38Z

1

Consider using substr

this.values[8] = this.values[8].substr(0,this.values[8].indexOf('?'))

answered Mar 15, 2019 at 13:42

Gwyn Rees

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Comments

berkay kılıç · Accepted Answer · 2019-03-15 13:41:49Z

0

You can use split method to divide text from ? as in example.

var link = "https://www.alibaba.com/product-detail/_60789694386.html?spm=a2700.galleryofferlist.normalList.1.5be41470uWBNGm&s=p"
var result = link.split('?')[0].replace("https://www.alibaba.com/product-detail/","");
console.log(result);

answered Mar 15, 2019 at 13:41

berkay kılıç

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Hassan ALAMI · Accepted Answer · 2019-03-15 13:43:23Z

0

Not sure i understood your problem, but try this

var s = 'https://www.alibaba.com/product-detail/_60789694386.html?spm=a2700.galleryofferlist.normalList.1.5be41470uWBNGm&s=p'
s = s.substring(0, s.indexOf('?'));
console.log( s );

answered Mar 15, 2019 at 13:43

Hassan ALAMI

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Comments

Niet the Dark Absol · Accepted Answer · 2019-03-15 13:45:04Z

0

For when you don't care about readability...

this.values[8] = new URL(this.values[8]).pathname.split("/").pop().replace(".html","");

answered Mar 15, 2019 at 13:45

Niet the Dark Absol

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Comments

User863 · Accepted Answer · 2019-03-15 13:48:47Z

0

Alternate, without using split

var link = "https://www.alibaba.com/product-detail/_60789694386.html?spm=a2700.galleryofferlist.normalList.1.5be41470uWBNGm&s=p"
var result = link.replace('https://www.alibaba.com/product-detail/', '').replace(/\?.*$/, '');
console.log(result);

answered Mar 15, 2019 at 13:48

User863

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Comments

Víñịt Vịłłă · Accepted Answer · 2019-03-15 13:53:20Z

0

You can use the regex to get it done. As of my knowledge you do something like:

    var v = "https://www.alibaba.com/product-detail/_60789694386.html?spm=a2700.galleryofferlist.normalList.1.5be41470uWBNGm&s=p"
    result = (v.match(/[^\/]+$/)[0]);
    result = result.substring(0,result.indexOf('?'));
    console.log(result);    // will return _60789694386.html

answered Mar 15, 2019 at 13:53

Víñịt Vịłłă

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