How to return custom Errorlevel in PowerShell?

Question

I want to run the script from command line, and get the error level. I use this batch script.

set log=C:\Users\PowerShell\XML\Log.txt
set PS=C:\Windows\System32\WindowsPowerShell\v1.0\powershell.exe
set PS=%PS%\powershell.exe 

"C:\Windows\System32\WindowsPowerShell\v1.0\powershell.exe" C:\Users\XML.ps1 -i C:\Users\A2.txt -j C:\Users\Fb.xml
   
echo %ERRORLEVEL% > "%log%"

I tried this script to get the custom errorlevel, If it is found, it will return 123, otherwise 456. But It always gives me 1.

$regex = [regex]$Pattern

$matching = $regex.Match($FBString)
if ($matching.Success) {
    while ($matching.Success) {
        "Match found: {0}" -f $matching.Value
        Exit 123
        $matching = $matching.NextMatch()
    }
}
else {
    "Not Found"
    Exit 456
}

Answer 1

Change the Exit to Return . Exit will exit your script. Return will return values that you wish for.

Answer 2

You can write the logic in your script
so any exit point will set the %errorlevel% system variable...

and create your "error return logic"...

something lihe this:

if ( $LASTEXITCODE -eq 0 ) { exit 0  }
if ( $LASTEXITCODE -eq 1 ) { exit 1  }
if ( $x -gt 1 ) { exit 2  }
if ( $x -lt 1 ) { exit 3  }
...

and then you can inspect from a batch file for %errorlevel% == 0, 1, 2, ...

Answer 3

Run the script with powershell -file. The default is powershell -command. Once that script is over, with -command the session is still going.

Answer 4

The problem is in the batch file. It should be like this :

set log=C:\Users\PowerShell\XML\Log.txt    

# Note the use of -File
"C:\Windows\System32\WindowsPowerShell\v1.0\powershell.exe" -ExecutionPolicy Bypass -File C:\Users\XML.ps1 -i C:\Users\A2.txt -j C:\Users\Fb.xml

echo %ERRORLEVEL% > "%log%"

For the first PowerShell script is correct already.