How to capture the http response as a Json Object in Java

Question

I want to send a HTTP request using CloseableHttpClient and then capture the body of the response in a JSON object so I can access the key values like this: responseJson.name etc

I can capture the response body as a string ok using the code below but how can I capture it as a JSON object?

CloseableHttpClient httpClient = HttpClients.createDefault();
URIBuilder builder = new URIBuilder();

    builder.setScheme("https").setHost("login.xxxxxx").setPath("/x/oauth2/token");

    URI uri = builder.build();
    HttpPost request = new HttpPost(uri);
    HttpEntity entity = MultipartEntityBuilder.create()
            .addPart("grant_type", grantType)
            .build();
    request.setEntity(entity);
    HttpResponse response = httpClient.execute(request);
    assertEquals(200, response.getStatusLine().getStatusCode());

    //This captures and prints the response as a string
    HttpEntity responseBodyentity = response.getEntity();
    String responseBodyString = EntityUtils.toString(responseBodyentity);
    System.out.println(responseBodyString);

What JSON library are you using?

dnault
– dnault

2019-03-06 17:19:03 +00:00
Commented Mar 6, 2019 at 17:19 — dnault
– dnault, Commented Mar 6, 2019 at 17:19

Sree · Accepted Answer · 2019-03-06 17:21:46Z

6

you can type cast your response string to JSON Object.

String to JSON using Jackson with com.fasterxml.jackson.databind:

Assuming your json-string represents as this: jsonString = "{"name":"sample"}"

import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;

ObjectMapper mapper = new ObjectMapper();
JsonNode node = mapper.readTree(responseBodyString);
String phoneType = node.get("name").asText();

Using org.json library:

JSONObject jsonObj = new JSONObject(responseBodyString);
String name = jsonObj.get("name");

answered Mar 6, 2019 at 17:21

Sree

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1 Comment

Matt Over a year ago

Great thanks Sree. I used JSONObject from your 2nd example. I had to add this to my POM: <dependency> <groupId>org.json</groupId> <artifactId>json</artifactId> <version>20180813</version> </dependency>

Ryuzaki L · Accepted Answer · 2019-03-06 17:22:59Z

0

Just convert the string into JSONObject then get the value for name

JSONObject obj = new JSONObject(responseBodyString);
System.out.println(obj.get("name"));

answered Mar 6, 2019 at 17:22

Ryuzaki L

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2 Comments

Matt Over a year ago

Thanks Deadpool. I have tried this but it says cannot resolve symbol 'JSONObject'. I have a 'JsonObject' available from com.google.json but nothing is recognised for JSONObject. Do I have to install a JAR or add something to my POM to access this?

Matt Over a year ago

Ah found it now, I added this to my POM: <dependency> <groupId>org.json</groupId> <artifactId>json</artifactId> <version>20180813</version> </dependency>

Ara Sho · Accepted Answer · 2019-03-06 17:25:36Z

What I would recommend is since you already have your JSON as a string, write a method which makes use of the google 'Splitter' object and define the characters on which you want to split into K-V pairs.

For example I did the same for K-V pairs as a string coming from a Spring Boot app and split based on the special ',' characters:

private Map<String, String> splitToMap(String in) {

    return Splitter.on(", ").withKeyValueSeparator("=").split(in);
}

replace with for example ": " and this should pick up your JSON string as K-V pairs.

Splitter Mvn dependency below:

<!-- https://mvnrepository.com/artifact/com.google.guava/guava -->
<dependency>
    <groupId>com.google.guava</groupId>
    <artifactId>guava</artifactId>
    <version>21.0</version>
</dependency>

hope this helps you make a start.

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