Set variable in bash script and access in expression in Azure Pipelines

Question

I am using an azure-pipelines.yml script to source control my build pipeline.

In a task I have defined a bash script to set some variables for certificates paths depending on whether we are building for production or anything else:

 steps:
  - bash: |
      echo "Building for $BUILD_SOURCEBRANCHNAME"
      if [ "$BUILD_SOURCEBRANCHNAME" = "production" ]; then
        echo "##vso[task.setvariable variable=configuration]Release"
        echo "##vso[task.setvariable variable=certificatesPath]${{ parameters.productionCertificatesPath }}"
      else
        echo "##vso[task.setvariable variable=configuration]Staging"
        echo "##vso[task.setvariable variable=certificatesPath]${{ parameters.stagingCertificatesPath }}"
      fi
    name: environmentVars

How can I then access these variables in an expression in a later build step in the same job? I know I can access them like $(environmentVars.configuration) and $(environmentVars.certificatesPath), but this syntax doesn't work for expressions. Here is where I'm trying to access the variables:

signingProvisioningProfileFile: ${{ format('{0}/app.mobileprovision', <ACCESS VARIABLE HERE>) }}

What is signingProvisioningProfileFile? Is that a build step parameter, or part of a Bash script? — Daniel Mann
– Daniel Mann, Commented Mar 5, 2019 at 1:42
$(configuration) and $(certificatesPath). If it's in another stage in the yaml file you'll need to use isOutput=true on your task.setvariable — jessehouwing
– jessehouwing, Commented Mar 5, 2019 at 10:56

Sam · Accepted Answer · 2019-03-21 00:36:24Z

2

My solution to this was to just bake the constants I wanted into the initial setting of the variable instead of trying to format it later. For example:

echo "##vso[task.setvariable variable=certificatesPath]${{ parameters.productionCertificatesPath }}/app.mobileprovision"

answered Mar 21, 2019 at 0:36

Sam

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