Array using for loop doesn't count elements Bash

Question

I'm learning to code with bash, I want to convert a decimal number to a binary array, the problem is that I can't count the number of elements in the array.

My code is:

read -p 'Ingrese primer numero: ' numero_1

function binario(){
 num=$1
 arr1=()
 i=0
 while [ $num -ne 0 ]
 do
  div=$(($num/2))
  rem=$(($num%2))
  num=$div
  arr1=("$rem" "${arr1[*]}")
  echo ${arr1[*]}
 done
 echo "array 1 es ${arr1[*]}"
 echo "largo dentro de la funcion ${#arr1[*]}"
}
binario $numero_1

the counting does not work. In my console, I obtain this information:

Ingrese primer numero: 56
array 1 es 1 1 1 0 0 0
largo dentro de la funcion 1

I know that I'm doing something wrong, but I don't know what, Can you please help me?

Thanks in advance

choroba · Accepted Answer · 2019-01-30 17:00:04Z

4

Replace the * with a @ to populate the array with the elements of the array instead of treating the whole array as one element:

- arr1=("$rem" "${arr1[*]}")
+ arr1=("$rem" "${arr1[@]}")

* expands to one word, @ expands to a list of words.

answered Jan 30, 2019 at 17:00

choroba

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