BASH Script Doesn't Exit Properly

Question

My BASH script doesn't exit properly.

#!/bin/bash  
#bootstrapper.sh
PIDD="$5"
while sleep 1; do kill -0 $PIDD || break; done
# Absolute path to this script. /home/user/bin/foo.sh
SCRIPT=$(readlink -f $0)
# Absolute path this script is in. /home/user/bin
SCRIPTPATH=`dirname $SCRIPT`
POSPAR1="$1" #-l
POSPAR2="$2" #location
POSPAR3="$3" #-d
POSPAR4="$4" #directory
cp -r -f $SCRIPTPATH/$4/* $2
rm -r -f $SCRIPTPATH/$4

The line:

while sleep 1; do kill -0 $PIDD || break; done

Is supposed to wait until the PID (stored in variable $PIDD) closes. It waits until it doesn't exist (the PID), but when it finally doesn't exist, it outputs: kill: 4: No such process. The rest of the script works as intended, but then the script doesn't terminate. Can I make the script terminate properly and not have that No such process be outputted?
Thanks again for all your help - I'm new to BASH/Linux.

Erik · Accepted Answer · 2011-03-26 17:48:27Z

3

while sleep 1; do kill -0 $PIDD 2>/dev/null || break; done

or

while kill -0 $PIDD 2>/dev/null; do sleep 1; done

answered Mar 26, 2011 at 17:48

Erik

91.7k13 gold badges203 silver badges192 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

BASH Script Doesn't Exit Properly

1 Answer 1

Comments

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Related