AngularJS - TypeError: fn is not a function [duplicate]

Question

I want to make a function being called in a certain interval of time inside the constructor. But I don't want to write the function inside the $interval statement because it's a little big. So I wanted to make something like this:

this.$interval(this.getSomething(), 1000);

And the initialize it outside of the controller's constructor:

getSomething = function getSomething(){
                 ...
};

But it gives me an error of TypeError: fn is not a function When it seems to me as a function... Any suggestions?

According to AngularJS $interval documentation it expects a callback. Changing your interval part to: this.$interval(this.getSomething, 1000); should work. (()removed) — dquijada
– dquijada, Commented Dec 18, 2018 at 10:19
@dquijada — Depends on if getSomething makes use of this internally or not. — Quentin
– Quentin, Commented Dec 18, 2018 at 10:20
Well, yes, @Quentin; but that's a more specific case. The only answer below can be checked for that case — dquijada
– dquijada, Commented Dec 18, 2018 at 10:23
And btw, @dquijada solution worked just fine. Thanks for the help :D — David Coelho
– David Coelho, Commented Dec 18, 2018 at 10:37

holydragon · Accepted Answer · 2018-12-18 10:15:51Z

-1

Try changing your function declaration to this.

getSomething = function(){
                 ...
};

and call your interval part like this.

this.$interval(function(){ this.getSomething() }, 1000);

answered Dec 18, 2018 at 10:15

holydragon

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2 Comments

Quentin Over a year ago

Using an anonymous function expression instead of a named function expression will not make any difference (unless the function tries to call itself recursively, in which case it will break it).

Quentin Over a year ago

function(){ this.getSomething() } won't work because the this context will have changed between functions.

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