Print different values with random in python 3.x

Question

from random import randint

result = []
colors = {1: "Red", 2: "Green", 3: "Blue", 4: "White"}

while True:
    for key in colors:
        ball = randint(1,4)
        probability = (ball/10)
        result.append(probability)

    break

print(result)

This code gives me 4 values which is ok, but I'd like to have no repetitions. So if program took e.g "White", it won't include it to iteration. Any ideas?

the while loop is pointless; and i'm not clear what you're trying to do, you iterate over colors but never use key — Chris_Rands
– Chris_Rands, Commented Dec 14, 2018 at 15:07
If you have a bigger list, and you need to draw n elements from it without replacement, you can just shuffle the list, and take draw = big_list[:n]. — L3viathan
– L3viathan, Commented Dec 14, 2018 at 15:10
@Hiddenguy well you need to specify the sample size, read the docs when you try a new function docs.python.org/3/library/random.html#random.sample — Chris_Rands
– Chris_Rands, Commented Dec 14, 2018 at 15:13

L3viathan · Accepted Answer · 2018-12-14 15:28:08Z

2

If you have 4 values and you just want a random permutation of them, just use random.shuffle:

from random import shuffle

colors = {1: "Red", 2: "Green", 3: "Blue", 4: "White"}

balls = list(colors)
shuffle(balls)
result = [ball/10 for ball in balls]

print(result)

Another option (especially good with larger lists, because shuffling a list is "slow") is the use of random.sample:

from random import sample

colors = {1: "Red", 2: "Green", 3: "Blue", 4: "White"}

result = [ball/10 for ball in sample(colors, 4)]

print(result)

edited Dec 14, 2018 at 15:28

answered Dec 14, 2018 at 15:09

L3viathan

27.5k2 gold badges63 silver badges84 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

L3viathan · Accepted Answer · 2018-12-15 15:36:36Z

0

You can check whether that particular value has been taken or not.

list_taken = []
number = randint(1,n)
while number in list_taken:
    number = randint(1,n)
list_taken.append(number)

So what above 4 lines of code do is, maintain a list of already taken values and repeat finding new values until it gets a new one.

Hope this helps!

edited Dec 15, 2018 at 15:36

L3viathan

27.5k2 gold badges63 silver badges84 bronze badges

answered Dec 14, 2018 at 15:30

Sumukha Pk

1241 silver badge7 bronze badges

Collectives™ on Stack Overflow

Print different values with random in python 3.x

2 Answers 2

Comments

Comments

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Related