print several strings using for loop in python

Question

I am trying to apply for loop in the print statement in Python 3.7.

For example

string1="Liverpool is always alone"
string2="Manchester United is the best team in the world"
string3="Tottenham Hotspur is for losers"
string4="Leicester City is overrated"

for i in range(1,5):
    print(string%i.find(" is"))  # <---this is the problem

My ultimate aim is to get

Sure, I can store the results in a list and then print the results like this:

 results=[string1.find(" is"),
          string2.find(" is"),
          string3.find(" is"),
          string4.find(" is")]

    for i in range(1,4):
        print(results[i])

But it will be troublesome especially when the number of string becomes too much.

Please suggest a way to print the multiple strings using for loop.

I'm using Python 3.7.

I would contest that declaring variables string1, string2, ... is more troublesome than storing all the strings in a list called strings (without declaring the variables). If you store all of them in a list, you can simply have for string in strings: print string.find(' is') — slider
– slider, Commented Nov 28, 2018 at 3:34

John Gordon · Accepted Answer · 2018-11-28 03:38:01Z

6

Put the strings in a list:

statements = [
    "Liverpool is always alone",
    "Manchester United is the best team in the world",
    "Tottenham Hotspur is for losers",
    "Leicester City is overrated",
]

Then you can easily loop over them:

for s in statements:
    print(s.find(" is"))

answered Nov 28, 2018 at 3:38

John Gordon

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2 Comments

Akarius Over a year ago

I agree about the list, then just [print(s.find(" is")) for s in statements] to print

MT32 Over a year ago

alright, I guess this is the closest I can ever get to concatenate integer with variable name in the print statement

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