I have a JSON string like below:
{
"MetaData": {
"ResourcesUsed": 1
},
"Result": [
{
"locations": [
{
"country": "Papua New Guinea",
"city": "Jacquinot Bay",
"locTypeAttributes": {
"localDate": "2018-10-08T04:21:00-07:00",
"utcDate": "2018-10-08T04:21:00-07:00",
},
"point": {
"coordinates": [
151.52,
-5.6
],
"type": "Point"
}
},{
"country": "Papua New Guinea2",
"city": "Jacquinot Bay2",
"locTypeAttributes": {
"localDate": "2018-10-08T04:21:00-07:00",
"utcDate": "2018-10-02T04:21:00-07:00",
},
"point": {
"coordinates": [
151.52,
-5.6
],
"type": "Point"
}
}
]
}
]
}
I converted it to a JSON object using Newtonsoft. What I want to do is to sort the locations array(s) inside the Result array by the utcDate field nested in each locations item. I found the following thread: C# Sort JSON string keys. However, I could not still implement it since I have arrays inside my object, while that question deals purely with sorting objects inside objects alphabetically by property name.
Here is a piece of code that I wrote so far:
public string GenerateJson()
{
var model = (JObject)JsonConvert.DeserializeObject(data);
Sort(model);
}
private void Sort(JObject jObj)
{
var props = jObj["Result"][0]["locations"].ToList();
foreach (var prop in props)
{
prop.Remove();
}
foreach (var prop in props.OrderBy(p => p.Name))
{
jObj.Add(prop);
if (prop.Value is JObject)
Sort((JObject)prop.Value);
if (prop.Value is JArray)
{
Int32 iCount = prop.Value.Count();
for (Int32 iIterator = 0; iIterator < iCount; iIterator++)
if (prop.Value[iIterator] is JObject)
Sort((JObject)prop.Value[iIterator]);
}
}
}
"Result": []array, or do you want to sort each"Result[*].locations"array? Because the locations themselves are an array so there might in principle be more than one, each with its ownutcDate. And if you do want to sort the"Results"array how do you want to deal with the situation where a result has multiple locations with multipleutcDatevalues? C# Sort JSON string keys is for recursively sorting a tree of objects by property name so it doesn't really apply here.utcDate.