I have python code like this
#! /usr/bin/python
from url parse import urlparse
url = 'https://pastebin.com/raw/EgGZmEqY'
parsed = urlparse(url)
site = parsed.netloc
print site
I want if the site is RAW or NOT just Grabbing the site without HTTPS and HTTP or WWW. For Example i have website like this from RAW. I want to get the URL just example.com without
https://example.com
http://example.com
www.example.com
example.com
How to get without https,http and www ? Thank you!
I take it that you just want the TLD (domain name) without the subdomains or scheme.
From this Stackoverflow answer, seems all you need is:
import tldextract
tldextract.extract('http://forums.news.cnn.com/')
ExtractResult(subdomain='forums.news', domain='cnn', suffix='com')
In your case then, i would use this: #!/usr/bin/env python3
import tldextract
url = 'https://www.pastebin.co.uk/raw/EgGZmEqY'
parsed = tldextract.extract(url)
domain = parsed.domain + '.' + parsed.suffix
print (domain)
