.sh file unable echo out variable that defined in bash

Question

I am trying to generate an HTML file with .sh and variable that defined in the shell

     [root@ip-xxx-xx-x-xxx Reporting]: IMAGE_TAG=xyzabc

.sh file code

      #!/bin/bash
      echo "<!DOCTYPE html>" > fargateproductiondeploy.html
      echo "<html> <body>" >> fargateproductiondeploy.html
     echo "<h2>Following Docker container 
     will be deployed  will be Deployed in production up on Approval </h2> 
     <ol>" >> fargateproductiondeploy.html
     echo "<li>$IMAGE_TAG </li>" >> fargateproductiondeploy.html

After running the ./generatehtml.sh out from HTML file was

            Following Docker container will be deployed will be Deployed in 
            production upon Approval 
            1.

Does it work if you first do export IMAGE_TAG=xyzabc ?

fvu
– fvu

2018-09-11 17:06:24 +00:00
Commented Sep 11, 2018 at 17:06 — fvu
– fvu, Commented Sep 11, 2018 at 17:06

chepner · Accepted Answer · 2018-09-11 17:08:08Z

You need to export the variable first

$ export IMAGE_TAG=xyzabc
$ ./generatehtml.sh

or source the file

$ IMAGE_TAG=xyzabc
$ . ./generatehtml.sh

Preferable to either would be to pass the value as an argument instead.

#!/bin/bash
image_tag=$1

echo "<!DOCTYPE html>" > fargateproductiondeploy.html
echo "<html> <body>" >> fargateproductiondeploy.html
echo "<h2>Following Docker container will be deployed  will be Deployed in production up on Approval </h2> <ol>" >> fargateproductiondeploy.html
echo "<li>$image_tag </li>" >> fargateproductiondeploy.html

followed by

$ ./generatehtml.sh xyzabc

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