Here is an example that I would like to print TRUE since Drug is in the string. If disease was in the string, I would like it to print TRUE as well. For all other cases I want to print FALSE
mystring = "Drug CID006338583 AC1O3UYX Stitch 1.515E-3 1.000E0 4.989E-2 5.235E-1 4 63 PTGES,SLC15A1,KLK8,IL7R"
check_if_in_mystring = ['Drug', 'Disease']
if check_if_in_mystring in mystring:
print("TRUE")
else:
print("FALSE")
Your example is correct you can use 'in' operator on string, just add a loop on 'check_if_in_mystring' to iterate over every element you want to check, like below example.
mystring = "Drug CID006338583 AC1O3UYX Stitch 1.515E-3 1.000E0 4.989E-2 5.235E-1 4 63 PTGES,SLC15A1,KLK8,IL7R"
check_if_in_mystring = ['Drug', 'Disease']
for element in check_if_in_mystring:
if element in mystring:
print("TRUE for {}".format(element))
else:
print("FALSE for {}".format(element))
output:
TRUE for Drug
FALSE for Disease
This snippet will detect if any one of check_if_in_mystring is in mystring:
any(word in mystring for word in check_if_in_mystring)
For the exact behavior from the question:
print(str(any(word in mystring for word in check_if_in_mystring)).upper())
converting string to list and checking in list can be one solution, as solved below.
mystring = "Drug CID006338583 AC1O3UYX Stitch 1.515E-3 1.000E0 4.989E-2 5.235E-1 4 63 PTGES,SLC15A1,KLK8,IL7R"
check_if_in_mystring = ['Drug', 'Disease']
mystring1 = mystring.split() #convertin string to list, seprated by white space
for item in check_if_in_mystring:
if item in mystring1:
print(item)
print("TRUE")
else:
print(item)
print("FALSE")
Output:printing work and its presence in mystring
Drug
TRUE
Disease
FALSE
mystring into a list.Try this:
>>> my_string = "Drug CID006338583 AC1O3UYX Stitch
1.515E-3 1.000E0 4.989E-2 5.235E-1 4 63 PTGES,SLC15A1,KLK8,IL7R"
>>> print("TRUE" if "Drug" in my_string or "Disease" in my_string else
"FALSE")
TRUE
>>> my_string = "Some other random string"
>>> print("TRUE" if "Drug" in my_string or "Disease" in my_string else
"FALSE")
FALSE
>>> my_string = "Has the word Disease"
>>> print("TRUE" if "Drug" in my_string or "Disease" in my_string else
"FALSE")
TRUE
strings support the in operator, so you can just check if Drug or Disease are in my_string.
Alex Taylor's on the right track, but the any clause can be greatly simplified:
>>> mystring = "Drug CID006338583 AC1O3UYX Stitch 1.515E-3 1.000E0 4.989E-2 5.235E-1 4 63 PTGES,SLC15A1,KLK8,IL7R"
>>> check_if_in_mystring = ['Drug', 'Disease']
>>> any(word in mystring for word in check_if_in_mystring)
True
>>> mystring = "Poodle CID006338583 AC1O3UYX Stitch 1.515E-3 1.000E0 4.989E-2 5.235E-1 4 63 PTGES,SLC15A1,KLK8,IL7R"
>>> any(word in mystring for word in check_if_in_mystring)
False
These approaches loop across the list of words in check_if_in_mystring, and any(...) returns True as soon as the first word in mystring expression is True. If the for word in check_if_in_mystring loop finishes without finding a True value, then any(...) returns False.
You may also use:
mystring.contains(anotherstring)
