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I have 8 elements and I want to add them into a array in numpy. I used np.append() but it seems that I can only add two elements at one time. I want to add all 8 elements at once. first_1 =35.72438966508524, first_2 = 35.73839550991734, etc.

35.72438966508524 35.73839550991734 35.81944190992304 
35.80549149559467 35.78399019604507 36.03781192909738 
35.9957696566448 35.94692998938782

np.append(first_1,first_2,first_3,first_4,first_5,first_6,first_7,first_8)

The error is

TypeError: append() takes from 2 to 3 positional arguments but 8 were given
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6
  • 1
    You probably want np.concatenate, but please format your question so it's at least somewhat readable. Commented Aug 15, 2018 at 21:38
  • I used it. But the error is concatenate() takes at most 3 arguments (8 given). Is there any other way I can add all of them? Commented Aug 15, 2018 at 21:41
  • 2
    You're probably calling it wrong. Use np.concatenate([a,b,c,d,e,f,g...]). Don't pass each array as an argument, pass a list of the arguments. In your case it would be np.concatenate([first_1,first_2,first_3,first_4,first_5,first_6,first_7,first_8]) Commented Aug 15, 2018 at 21:41
  • the code is np.concatenate([first_1,first_2,first_3,first_4,first_5,first_6,first_7,first_8]). Still got an error: ValueError: zero-dimensional arrays cannot be concatenated Commented Aug 15, 2018 at 21:44
  • 1
    Then please provide an minimal reproducible example, as you have not shown enough information to solve your problem. Commented Aug 15, 2018 at 21:44

3 Answers 3

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4 
first = 35.72438966508524 
second = 35.73839550991734 
third = 35.81944190992304
forth = 35.80549149559467 
fifth = 35.78399019604507 
sixth = 36.03781192909738 
seventh = 35.9957696566448 
eighth = 35.94692998938782

now to make a new numpy array:

a = np.array([first, second, third, forth, fifth, sixth, seventh, eighth])

output:

a
Out[89]: 
array([35.72438967, 35.73839551, 35.81944191, 35.8054915 , 35.7839902 ,
       36.03781193, 35.99576966, 35.94692999])

to append to existing array (using previously created 'a'):

a = np.append(a, [first, second, third, forth, fifth, sixth, seventh, eight], axis=0)

which gives:

a
Out[93]: 
array([35.72438967, 35.73839551, 35.81944191, 35.8054915 , 35.7839902 ,
       36.03781193, 35.99576966, 35.94692999, 35.72438967, 35.73839551,
       35.81944191, 35.8054915 , 35.7839902 , 36.03781193, 35.99576966,
       35.94692999])
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Comments

3

Correct syntax is (if I suppose that you wanted to append your 8 values to an numpy array named as ar:

np.append(ar, (first_1, first_2, first_3, first_4, first_5, first_6, first_7, first_8))
  • The first argument is your original numpy array,
  • The second one is the tuple (or the list, or other array-like object) of your values, so those values have to be in the parentheses.
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Comments

1 
np.array([first_1,first_2,first_3,first_4,first_5,first_6,first_7,first_8])
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4 Comments

TypeError: append() missing 1 required positional argument: 'values'. What does it mean?
@user3483203 first_1... aren't arrays, they are numbers lol
Well this was a terribly unclear question, my mistake :)
@user3483203 ahaha no problem, I did a double take as well, she worded it pretty poorly.

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