Calculate Local Binary Pattern with radius

Question

I'm confused with a local binary pattern that uses radius. I have read the journal by Ojala et al, where they use this equation to calculate the center pixel :Eq.1

Where :Eq.2

with :
R = Radius
P = amount of neighborhood pixel
gp = neighborhood pixel
gc = center pixel

for example R=2;P=16(from 0-15)
if s(g15-gc)=1 and the other is 0

so the LBP value is:
LBP=1*2^15=32768

so, how this big value turn into pixel value?

you can see this project for working swift example github.com/BradLarson/GPUImage2/tree/master/examples/Mac/… — johndpope
– johndpope, Commented Aug 22, 2018 at 15:14

Owais Ch · Accepted Answer · 2018-07-23 07:15:51Z

2

This is not how LBP works, it calculates the value of neighboring pixels (i.e 0 or 1). Then LBP makes a pattern of it for example 1101101 which is in some binary form. After that it converts the binary value to decimal value. **

**> We will put that value in pixel value as lbp works on gray images so

it wont matter how big the value is.**

**

For more explaination see the picture below https://slideplayer.com/slide/4512194/15/images/18/LBP(Local+Binary+Pattern).jpg

edited Jul 23, 2018 at 7:15

answered Jul 23, 2018 at 6:59

Owais Ch

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