Run bash script with Django

Question

I'm really new in django. I need to run a bash script when I push a button in html, and I need to do it with Django Framework, because I used it to build my web. I'd be grateful if anybody could help me

Edit: I have added my template and my views for being more helpful. In the 'nuevaCancion' template, I use 2 views.

<body>
	
	{% block cabecera %}
	<br><br><br>
	<center>
	<h2> <kbd>Nueva Cancion</kbd> </h2>
	</center>
	{% endblock %}
	
	{% block contenido %}

		<br><br>
		<div class="container">
    		<form id='formulario' method='post' {% if formulario.is_multipart %} enctype="multipart/form-data" {% endif %} action=''>
				{% csrf_token %}
    			<center>
				<table>{{formulario}}</table>
        		<br><br>
        		<p><input type='submit' class="btn btn-success btn-lg" value='Añadir'/>
				 <a href="/ListadoCanciones/" type="input" class="btn btn-danger btn-lg">Cancelar</a></p>
				</center>
      	</form>
    	<br>
	</div>
	<center>
		<form action="" method="POST">
    		{% csrf_token %}
    		<button type="submit" class="btn btn-warning btn-lg">Call</button>
		</form>
	</center>
	{% endblock %}

</body>

Views.py

def index(request):
    if request.POST:
    subprocess.call('/home/josema/parser.sh')

    return render(request,'nuevaCancion.html',{})

parser.sh

#! /bin/sh
python text4midiALLMilisecs.py tiger.mid

stackoverflow.com/questions/4256107/…

Lucas Lima
– Lucas Lima

2018-07-04 16:57:41 +00:00
Commented Jul 4, 2018 at 16:57 — Lucas Lima
– Lucas Lima, Commented Jul 4, 2018 at 16:57

Rounak · Accepted Answer · 2019-07-09 06:04:24Z

16

You can do this with empty form.

In your template make a empty form

# index.html
<form action="{% url 'run_sh' %}" method="POST">
    {% csrf_token %}
    <button type="submit">Call</button>
</form>

Add url for your form

from django.conf.urls import url

from . import views

urlpatterns = [
    url(r'^run-sh/$', views.index, name='run_sh')
]

Now in your views.py you need to call the bash.sh script from the view that returns your template

import subprocess

def index(request):
    if request.POST:
        # give the absolute path to your `text4midiAllMilisecs.py`
        # and for `tiger.mid`
        # subprocess.call(['python', '/path/to/text4midiALLMilisecs.py', '/path/to/tiger.mid'])

        subprocess.call('/home/user/test.sh')

    return render(request,'index.html',{})

My test.sh is in the home directory. Be sure that the first line of bash.sh have sh executable and also have right permission. You can give the permissions like this chmod u+rx bash.sh.

My test.sh example

#!/bin/sh
echo 'hello'

File permision ls ~

-rwxrw-r--   1 test test    10 Jul  4 19:54  hello.sh*

edited Jul 9, 2019 at 6:04

Rounak

8147 silver badges16 bronze badges

answered Jul 4, 2018 at 17:04

Druta Ruslan

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16 Comments

Josema_23 Over a year ago

I'm trying what you say, but I think I'm missing something in my code because it doesn't work, where could I show my script and what I've done? Also, do I have to add some url or it is not needed?

Josema_23 Over a year ago

I have added them yet :)

Druta Ruslan Over a year ago

you have two forms, and you say the you use two views function for one template, try to add new url and add this url to form action

Druta Ruslan Over a year ago

i update my answer, i added the urls and add action to form

Druta Ruslan Over a year ago

your bash.sh file contains only this line of code ? python text4midiALLMilisecs.py tiger.mid ?

|

Muhtar · Accepted Answer · 2018-07-04 17:05:52Z

2

You can use python module subprocess in your view.


import subprocess

def your_view(request):

    subprocess.call('your_script.sh')

answered Jul 4, 2018 at 17:05

Muhtar

336 bronze badges

Comments

Nijil · Accepted Answer · 2018-11-15 14:17:25Z

You can refer my blog for detailed explanation >>

http://www.easyaslinux.com/tutorials/devops/how-to-run-execute-any-script-python-perl-ruby-bash-etc-from-django-views/

I would suggest you to use Popen method of Subprocess module. Your shell script can be executed as system command with Subprocess.

Here is a little help.

Your views.py should look like this.

from subprocess import Popen, PIPE, STDOUT
from django.http import HttpResponse

def main_function(request):
    if request.method == 'POST':
            command = ["bash","your_script_path.sh"]
            try:
                    process = Popen(command, stdout=PIPE, stderr=STDOUT)
                    output = process.stdout.read()
                    exitstatus = process.poll()
                    if (exitstatus==0):
                            result = {"status": "Success", "output":str(output)}
                    else:
                            result = {"status": "Failed", "output":str(output)}

            except Exception as e:
                    result =  {"status": "failed", "output":str(e)}

            html = "<html><body>Script status: %s \n Output: %s</body></html>" %(result['status'],result['output'])
            return HttpResponse(html)

In this example, stderr and stdout of the script is saved in variable 'output', And exit code of the script is saved in variable 'exitstatus'.

Configure your urls.py to call the view function "main_function".

url(r'^the_url_to_run_the_script$', main_function)

Now you can run the script by calling http://server_url/the_url_to_run_the_script

Shameer Kashif · Accepted Answer · 2018-07-04 17:04:18Z

1

Do it with Python:

With Subprocess:

import subprocess
proc = subprocess.Popen("ls -l", stdout=subprocess.PIPE)
output, err = proc.communicate()
print output

Or with os module:

import os
os.system('ls -l')

answered Jul 4, 2018 at 17:04

Shameer Kashif

4443 silver badges17 bronze badges

Comments

Anupam · Accepted Answer · 2021-01-28 14:03:05Z

From Python 3.5 onwards, subprocess.run() is the recommended approach

As per the doc;

The recommended approach to invoking subprocesses is to use the run() function for all use cases it can handle. For more advanced use cases, the underlying Popen interface can be used directly.

The run() function was added in Python 3.5; if you need to retain compatibility with older versions, see the Older high-level API section.

As in this example,

import subprocess

def index(request):
    if request.POST:
        subprocess.run(['/home/josema/parser.sh'])

    return render(request,'nuevaCancion.html',{})

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