I have a string
Best product25.075.0Product29.029.0
And now I need to split this string to
'Best product' '25.0' '75.0' , 'Product' '29.0' '29.0'
How can i achieve this?
2 Answers
You can use re.findall to find all words (containing letter or space - matching pattern [a-zA-Z ]+) or all numbers (one or more digits followd by a dot and zero - matching pattern \d+.0)
string = 'Best product25.075.0Product29.029.0'
import re
re.findall(r'[a-zA-Z ]+|\d+(?:.0)?', string)
# ['Best product', '25.0', '75.0', 'Product', '29.0', '29.0']
3 Comments
Heiner Früh
note that this will only work if the "words" dont contain any numbers
Chaban33
Than it will be a problem
Sunitha
@HeinerFrüh Updated the answer to work with words containing numbers without decimal points
A very similar way to do it is:
import re
string = 'Best product25.075.0Product29.029.0'
re.findall(r'[^\d]+|\d+.0', string)
The code only distinguishes between non-digits [^\d]+ and digits plus dot zero \d+.0'. So it matches also additional characters like _.
"25.075.0"is inherently ambiguous, though. Is it"25.0", "75.0"or"25.07", "5.0"? You need to assume that each number has exactly one place after the decimal point for any of the answers to work. It would be better if you could modify whatever produces that string to use a separating character.