iOS App xcode build errors

Question

I am new to iOS development and struggling with few build errors. I looked up the web on how to fix these errors but could not get a hint. Using Xcode 9.4 with built in Swift.

'LaunchOptionsKey' is not a member type of 'UIApplication'
Instance member 'state' cannot be used on type 'UIControl'
Instance member 'state' cannot be used on type 'UIControl'
Type 'UIControl' has no member 'State'

Link is below as I was not allowed to include the screenshot in this post.

Xcode build errors

U. Benlice · Accepted Answer · 2018-06-11 10:00:02Z

29

It should be like this :

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    return true
}

edited Jun 11, 2018 at 10:00

answered Jun 11, 2018 at 9:26

U. Benlice

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5 Comments

Omanex Jeep Adventures Over a year ago

Thank you, I replaced the code with your recommendation, it worked but needed me to add a boolean return value .. thank you. I am still trying to fix the other errors. I will try to paste the codes here too

U. Benlice Over a year ago

You can read apple document about this methods requirements. developer.apple.com/documentation/uikit/uiapplicationdelegate#//…:

Omanex Jeep Adventures Over a year ago

Thanks Benlice, indeed I think I need to spend more time reading and understanding the docs, somehow all codings look strange symbols to me :-) hopefully it is a matter of time and efforts to get there ..thanks for the advice

user3207158 Over a year ago

Same question here. I fixed the problem using what you showed. However I find it very hard to reconcile this with the fact that UIApplication.LaunchOptionsKey is indeed a structure. How does this work? Link: developer.apple.com/documentation/uikit/uiapplication/…

instanceof Over a year ago

But on Apple's documentation, it shows the same format of the asker, namely UIApplication.LaunchOptionsKey. How are we supposed to know which one is correct?

sp_nz · Accepted Answer · 2019-03-31 04:50:06Z

Neither the original question nor the accepted answer note that the code with the error is generated code when a project is created and as such generally shouldn't need to be changed.

The problem is because of the version of Xcode. UIApplicationLaunchOptionsKey has been renamed to UIApplication.LaunchOptionsKey in the newer version of Xcode (10.2). I came across this when I tried to open my project in an older version of Xcode. This sucks because I now can't work on my project on my older computer that can't be updated to the latest version.

Val · Accepted Answer · 2019-11-03 21:23:14Z

2

I am running Xcode 9.3 and Android Studio 3.5.1.

All I did was remove the "." on the definition:

UIApplication.LaunchOptionsKey: Any

To:

UIApplicationLaunchOptionsKey: Any

without the period. Works like a charm! Enjoy.

answered Nov 3, 2019 at 21:23

Val

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