I have 2 arrays, array a contains keys and array b contains their values
let a = ['name', 'options', 'address', 'options', 'gender', 'options'];
let b = ['john doe', 'a', 'india', 'b', 'male', 'c'];
I want output like this
{
'name': 'john doe',
'options': 'a, b, c',
'address': 'india',
'gender': 'male'
}
Use Array.reduce
let a = ['name', 'options', 'address', 'options', 'gender', 'options'];
let b = ['john doe', 'a', 'india', 'b', 'male', 'c'];
let r = a.reduce((o,c,i) => {o[c] = o[c] ? o[c] + ", " + b[i]:b[i]; return o;}, {})
console.log(r);An alternative method would be as shown below. This loops for a.length amount of times, gets the value of a and adds it as a key to c, where the key's value is the value from b. Here is a breakdown of how it works:
For each element in a: if there exists no element in c with the keyname a[i], create the key and set it to the value from b[i]. If the element does already exist in c (then the key must represent an array, not a single item), if that value is a single item, make it an array, and re insert that first value, then in any case, push the new item to that array.
let a = ['name', 'options', 'address', 'options', 'gender', 'options','options'];
let b = ['john doe', 'a', 'india', 'b', 'male', 'c', 'd'];
let c = {};
for (let i=0; i<a.length; i++) {
if (typeof c[a[i]] === 'undefined') {
c[a[i]] = b[i];
} else {
if (c[a[i]] instanceof Array === false) {
c[a[i]] = [c[a[i]]];
}
c[a[i]].push(b[i]);
}
}
console.log(c);
invert(object){
let invertedObject ={};
for(let key in object){
const originalValue = object[key];
invertedObject = {originalValue : key}
}
return invertedObject
}
let a = ['name', 'options', 'address', 'options', 'gender', 'options'];
let b = ['john doe', 'a', 'india', 'b', 'male', 'c'];
let r = a.reduce((o,c,i) => {o[c] = o[c] ? o[c] + ", " + b[i]:b[i]; return o;}, [])
console.log(r);
a, b, cmap to options? Seems like you're going to have to do this manuallyaarray contains options trice, so it's still one-to-one mapping.